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anastassius [24]
3 years ago
5

A boat can move at a constant velocity of 8 km/h in still water. How long will it take for the boat to move 24 km?

Physics
1 answer:
Elis [28]3 years ago
4 0

Answer: D.) 3hrs

Explanation:

Given the following :

A boat can move at a constant velocity of 8 km/h; How long will it take for the boat to move 24 km

Recall:

Velocity = Displacement / time

For the boat to travel a distance of 24 km at a constant velocity of 8km /hr

Time taken = Displacement(distance moved) / velocity

Time taken = 24km / 8kmhr^-1

Tine taken = 3hrs

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No sand doesn't stay sand forever.

Explanation:

  • We may have a thought that the sand we see on the beach areas are always the same one for eternal, but it is not true.
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Why can you get a shock if you touch a metal doorknob after walking across a wool carpet? (1 Point) You have gained electrons; t
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Why can you get a shock if you touch a metal doorknob after walking across a wool carpet is because you have gained neutrons; the doorknob has fewer electrons. This is further explained below.

<h3>What are electrons?</h3>

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2 years ago
A helicopter is hovering above the ground. Jim reaches out of the copter (with a safety harness on) at 180 m above the ground. A
vesna_86 [32]

Answer:

The maximum height of the package is 140 m above the ground. Jim Bond will not catch the package.

Explanation:

Hi there!

The equation of height and velocity of the package are the following:

h = h0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

h = height of the package at time t.

h0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² because we consider the upward direction as positive).

v = velocity of the package at a time t.

First, let´s find the time it takes the package to reach the maximum height. For this, we will use the equation of velocity because we know that at the maximum height, the velocity of the package is zero. So, we have to find the time at which v = 0:

v = v0 + g · t

0 = 50.5 m/s - 9.8 m/s² · t

Solving for t:

-50.5 m/s / -9.81 m/s² = t

t = 5.15 s

Now, let´s find the height that the package reaches in that time using the equation of height. Let´s place the origin of the frame of reference on the ground so that the initial position of the package is 10 m above the ground:

h = h0 + v0 · t + 1/2 · g · t²

h = 10 m + 50.5 m/s · 5.15 s - 1/2 · 9.81 m/s² · (5.15 s)²

h = 140 m

The maximum height of the package is 140 m above the ground. Jim Bond will not catch the package.

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