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dybincka [34]
3 years ago
12

How many atomospheres are in 710 mm Hg

Chemistry
2 answers:
timofeeve [1]3 years ago
5 0

Answer:

0.934210526 atmospheres

Explanation:

Ierofanga [76]3 years ago
3 0

Answer:

Explanation:

1 atm = 760 mmHg

x atm = 710 mmHg

710/760 = x

71/76 =x

x about 0,93 atm

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Consider the following reaction, equilibrium concentrations, and equilibrium constant at a particular temperature. Determine the
liraira [26]

Answer:

1.4 * 10^-3

Explanation:

The equilibrium expression can be written as follows:

Keq = P [HD]^2/[ P[H2] * P[D2]]

Where P is pressure

1.80= (2.7 * 10^-3)^2 / ( 1.1 * 10^-3 * P[H2])

P[H2] = [2.7 * 10^-3]^2 / [1.8 * 1.1 * 10^-3]

P[H2] = 1.4 * 10^-3 atm

4 0
3 years ago
Why are group 18 elements unable to form ionic bonds?
meriva
Because their valence shell have stable electrons so they can't gain or loose electrons.
in ionic bonds the elements should gain or loose electrons
7 0
3 years ago
Given the following values of pKa, determine which is the weakest base of the answers listed. Acid pKa HClO2 1.95 HClO 7.54 HCOO
professor190 [17]

Answer:

HClO 7.54

Explanation:

Hypochlorous acid (HClO) is a weakest acid because the pKa value of Hypochlorous acid is very high among the options given in the activity. pKa is a method which is used in order to identify the strength of an acid. The higher the value of pKa of a liquid, lower the strength of an acid while lower the value of pKa of chemical, higher the strength of an acid. In the options, HClO2  is a strong acid due to high lower pKa value.

4 0
4 years ago
A solution prepared by dissolving 0.100 mole of propionic acid in enough water to make 1.00 L of solution is observed to have a
torisob [31]

Answer:

C) k_a=1.3\times 10^{-5}

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

Thus,  

pH = - log [H⁺]

The expression of the pH of the calculation of weak acid is:-

pH=-log(\sqrt{k_a\times C})

Where, C is the concentration = 0.5 M

Given, pH = 2.94

Moles = 0.100 moles

Volume = 1.00 L

So, Molarity=\frac{Moles}{Volume}=\frac{0.100}{1.00}\ M=0.100\ M

C = 0.100 M

2.94=-log(\sqrt{k_a\times 0.100})

\log _{10}\left(\sqrt{k_a0.1}\right)=-2.94

\sqrt{0.1}\sqrt{k_a}=\frac{1}{10^{2.94}}

k_a=1.3\times 10^{-5}

4 0
3 years ago
Uestion 1 how many grams of disodium ethylenediaminetetraacetate (molar mass = 372.24 g/mol) required to prepare 500. ml of a 0.
Jlenok [28]
The solution is as follows:

Important data:
*0.01 M solution = 0.01 moles <span>disodium ethylenediaminetetraacetate/ L solution
*1 L = 1000 mL
*Molar mass = 372/24 g/mol

Stoichiometric calculation:
0.01 mol/L * (1 L/1000 mL) * 500 mL * </span><span>372.24 g/mol = 1.8612 g

Therefore, you would need 1.8612 grams of </span>disodium ethylenediaminetetraacetate.
6 0
3 years ago
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