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chubhunter [2.5K]
3 years ago
13

What can be expected to occur as climate change continues on earth?

Chemistry
1 answer:
Zanzabum3 years ago
7 0
<span>the earth's temperature will continue to rise which will increase the amount of sea ice that is melting

hope this helped</span>
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6) Determine la concentración de una solución que ha sido preparada añadiendo 80cc de agua a 320cc de solución alcohólica al 20%
Xelga [282]

Answer:

16% v/v es la nueva concentración de alcohol en la solución

Explanation:

El porcentaje volumen/volumen (% v/v) es definido como 100 veces la relación entre el volumen de soluto (Alcohol en este caso) y el volumen total de la solución (Agua + Alcohol). Para resolver esta pregunta necesitamos hallar el volumen de alcohol y el de agua:

<em>Volumen alcohol:</em>

320cc * (20cc etanol / 100cc) = 64cc etanol

<em>Volumen agua:</em>

80cc + (320cc-64cc) = 336cc agua

<em>% v/v:</em>

64cc / (336cc + 64cc) * 100

= 16% v/v es la nueva concentración de alcohol en la solución

3 0
3 years ago
True or false: The force exerted onto an object must be perpendicular to the displacement if work is to be considered done.
RUDIKE [14]

Answer:

its letter B. false

Explanation:

bjchakfbhc

4 0
3 years ago
Please answer this question
ZanzabumX [31]

Answer:

Is the fixed number of water molecules present in one formula unit of a substance

Explanation:

When copper sulphate is heated in a china dish, the blue colomed crystal changes to a white powder due to the removal of molecules of water of crystallization

6 0
3 years ago
Which of the following is not an example of a molecule A. Mn     B. KOH    C. O₃    D. H₂S
goldenfox [79]

look at the chemical tables.  but i believe it is A

3 0
3 years ago
Read 2 more answers
Gaseous methane (CH4) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO) and gaseous water (H2O) . Suppo
Leto [7]

Answer:

0 g.

Explanation:

Hello,

In this case, since the reaction between methane and oxygen is:

CH_4+2O_2\rightarrow CO_2+2H_2O

If 0.963 g of methane react with 7.5 g of oxygen the first step is to identify the limiting reactant for which we compute the available moles of methane and the moles of methane consumed by the 7.5 g of oxygen:

n_{CH_4}=0.963gCH_4*\frac{1molCH_4}{16gCH_4}=0.0602molCH_4\\ \\n_{CH_4}^{consumed}=7.5gO_2*\frac{1molO_2}{32gO_2}*\frac{1molCH_4}{2molO_2} =0.117molCH_4

Thus, since oxygen theoretically consumes more methane than the available, we conclude the methane is the limiting reactant, for which it will be completely consumed, therefore, no remaining methane will be left over.

left\ over=0g

Regards.

7 0
3 years ago
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