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3 years ago

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You are analyzing an open-return wind tunnel that intakes air at 20 m/s and 320K. When the flow exits the wind tunnel it is movi

ng at a speed of 250 m/s. What is the temperature of the flow exiting that wind tunnel

2 answers:

11111nata11111 [884]3 years ago

8 0

The solution is in the attachment

Vedmedyk [2.9K]3 years ago

6 0

Answer:

please find attached.

Explanation:

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Which of the following headlines about the French Revolution is not true?

Sever21 [200]

Answer:

d) "Napoleon Declares Himself Holy Roman Emperor"

Explanation:

The French Revolution is defined as a period of the major social upheaval which began in the year 1787 and lasted till year 1799. This revolution completely redefined the the very nature of the political power in France. and also the relationship between the rulers of France and the people they governed.

The 1789 Estates-General was the 1st meeting since year 1614 of the French Estates-General. It is a general assembly which represents the French estates of realm.

During the French revolution was at peak, the National Assembly issued the Declaration of the rights of the man to the public.

Maximilien Robespierre was considered to be one of the most influential figure and most important statesman during the French Revolution.

Thus all the options (a),(b) and (c) are headlines about the French Revolution, except option (d).

3 0

3 years ago

Air in a piston–cylinder assembly, initially at 3 bar, 142 K, and a volume of 2 m3. The air undergoes a process to a state where

Archy [21]

Answer:

mass of the air = 14.62kg

Workdone = 415.88 kJ

Heat transfer = 415.88 kJ

Explanation:

Please find the attached files for the solution

6 0

3 years ago

Read 2 more answers

Calculate the biaxial stresses σ1 and σ2 for the biaxial stress case, where ε1 = .0020 and ε2 = –.0010 are determined experiment

Llana [10]

Answer:

i) σ1 = 133.5 MPa

σ2 = -2427 MPa

ii) 78.89 MPa

Explanation:

Given data:

ε1 = 0.0020 and ε2 = –0.0010

E = 71 GPa

v = 0.35

<u>i) Determine the biaxial stresses σ1 and σ2 using the relations below</u>

ε1 = σ1 / E - v (σ2 / E) -----( 1 )

ε2 = σ2 / E - v (σ1 / E) -------( 2 )

resolving equations 1 and 2

σ1 = E / 1 - v^2 { ε1 + vε2 } ---- ( 3 )

σ2 = E / 1 - v^2 { ε2 + vε1 } ----- ( 4 )

input the given data into equation 3 and equation 4

σ1 = 133.5 MPa

σ2 = -2427 MPa

<u>ii) Calculate the value of the maximum shear stress ( Zmax )</u>

Zmax = ( σ1 - σ2 ) / 2

= 133.5 - ( - 2427 ) / 2

= 78.89 MPa

3 0

3 years ago

What regulations is OSHA cover under what act

andriy [413]

The law requires employers to provide their employees with working conditions that are free of known dangers. The OSH Act created the Occupational Safety and Health Administration (OSHA), which sets and enforces protective workplace safety and health standards.

6 0

3 years ago

A tank contains initially 2500 liters of 50% solution. Water enters the tank at the rate of 25 iters per minute and the solution

sergejj [24]

Answer:

Percentage of solution=32. 96%

Explanation:

Given that initially tank have 50% solution.It means that amount of solution=0.5 x 2500 =1250 lts

Lets take the amount of solution at time t = A

So

$\dfrac{dA}{dt}=rate\ in\ solution -rate\ out\ solution$

$\dfrac{dA}{dt}=concentration\times rate\ in\ of\ water -concentration\times rate\ out\ of\ water$

$\dfrac{dA}{dt}=0\times 25-\dfrac{A}{2500}\times 50$

$\dfrac{dA}{dt}=-\dfrac{A}{50}$

Now by integration

$\ln A=-\dfrac{1}{50}t+C$

Where C is the constant

Given that at t=0 ,A=1250

So $C=\ln 1250$

$\ln A=-\dfrac{1}{50}t+\ln 1250$

When t=20 min

$\ln A=-\dfrac{1}{50}\times 20+\ln 1250$

A=837.90

So percentage of solution after 20 min

$=\dfrac{1250-837.9}{1250}\times 100$

Percentage of solution=32. 96%

4 0

3 years ago