Estructura molecular del óxido nitroso

imagine you have four food dyes to test A, B, C and D imagine that you are going to investigate which food dye diffuses more qui

Lady_Fox [76]

Answer:

You will change which food dye is used. You will measure how quickly the dyes diffuse. You could use a timer to see how long the dye takes to completely diffuse.

5 0

3 years ago

The balanced chemical equation, 2NO (g) + 5H2 (g) (Arrow pointing this way >>) 2NH3 (g) + 2H2O (g), can be expressed in wo

PolarNik [594]

Both B AND D are correct and same

5 0

3 years ago

Read 2 more answers

A solution of sodium chloride in water has a vapor pressure of 19.6 torr at 25°C. What is the mole fraction of NaCl in this solu

Debora [2.8K]

Answer:

Mole fraction of Nacl is 0.173

Explanation:

we know that

$P_{sol}=\chi_{solvent}P^0_{solvent}$

where,

P sol - the vapor pressure of the solution

χ solvent - the mole fraction of the solvent

P ∘ solvent - the vapor pressure of the pure solvent

This means that in order to be able to calculate the mole fraction of sodium chloride, you need to know what the vapor pressure of pure water is at

25 ° C You can use an online calculator to find that the vapor pressure of pure water at 25 C is equal to about 23.8 torr .

$\chi_{water}= \frac{P{sol}}{P^0{water}}$

$\chi_{water}= \frac{19.6}{23.8}$

=0.827

Also we know that

$\chi_{water}+\chi_{Nacl}= 1$

This means that the mole fraction of sodium chloride is

χ_{Nacl}= 1-Χ_{water}

= 1-0.827 =0.173

3 0

3 years ago

Help me please!!!

LiRa [457]

Answer:

0.052L

Explanation:

Molarity of a substance, which refers to the molar concentration, is calculated as follows:

Molarity (M) = number of moles (mol) ÷ volume (L)

Mole = mass ÷ molar mass

Molar Mass of AgNO3 since Ag = 108, N = 14, O = 16

108 + 14 + 16(3)

= 108 + 14 + 48

= 170g/mol

Mole = 21.89 g ÷ 170g/mol

Mole = 0.129moles

Using Molarity (M) = number of moles (mol) ÷ volume (L)

Volume = number of moles ÷ molarity

V = 0.129 ÷ 2.50

V = 0.0516

To the correct significant figure i.e. 4s.f, the numerical value of volume = 0.052L

8 0

3 years ago

Chlorine is the most widely used disinfectant for killing pathogens during water treatment. Determine the kilograms of chlorine

makkiz [27]

Explanation:

The given data is as follows.

Flow of chlorine (Q) = $10,000 m^{3}/day$

Amount of liter present per day is as follows.

$10,000 \times 10^{3} l/day$

It is given that dosage of chlorine will be as follows.

10 mg/l = $10 \times 10^{-6}$ kg/l

Therefore, total chlorine requirement is as follows.

Total chlorine requirement = $(10,000 \times 10^{3}) \times (10 \times 10^{-6})$ kg/day

= 100 kg/day

Thus, we can conclude that the kilograms of chlorine used daily at the given water treatment plant is 100 kg/day.

4 0

3 years ago

Estructura molecular del óxido nitroso​

Estructura molecular del óxido nitroso