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lina2011 [118]
1 year ago
13

i have a balloon that can hold 100 liters of air. if i blow up this balloon with 3 moles of oxygen gas at a pressure of 1.0 atmo

sphere, what is the temperature of the balloon?
Chemistry
1 answer:
Tcecarenko [31]1 year ago
4 0

Baloon with 3 moles og oxygen at 1 atm.The temperature of the balloon is <u>4 Kelvin</u>.

An ideal gas is a theoretical gas composed of many randomly transferring factor particles that aren't difficult to interparticle interactions. the best gasoline idea is beneficial because it obeys the precise gas law, a simplified equation of country, and is amenable to evaluation under statistical mechanics.

An ideal gas is described as one for which both the extent of molecules and forces between the molecules are so small that they have got no effect at the behavior of the gas. The real gas that acts almost like a really perfect gasoline is helium. that is due to the fact helium, in contrast to maximum gases, exists as an unmarried atom, which makes the van der Waals dispersion forces as low as viable

Using the ideal gas equation:-

Given;

P₁ = 1 atm

V₁ = 100  L

n = 3

r = 8.314

T = PV/nR

  = 1 × 100 / 3 × 8.314

 = 4 K

Learn more about ideal gas here:-brainly.com/question/20348074

#SPJ4

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Answer : The equilibrium concentration of CH_3OH will be, (C) 2.82\times 10^{-1}

Explanation :  Given,

Equilibrium constant = 14.5

Concentration of CO at equilibrium = 0.15 M

Concentration of H_2 at equilibrium = 0.36 M

The balanced equilibrium reaction is,

CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)

The expression of equilibrium constant for the reaction will be:

K_c=\frac{[CH_3OH]}{[CO][H_2]^2}

Now put all the values in this expression, we get:

14.5=\frac{[CH_3OH]}{(0.15)\times (0.36)^2}

[CH_3OH]=2.82\times 10^{-1}M

Therefore, the equilibrium concentration of CH_3OH will be, (C) 2.82\times 10^{-1}

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<em>good luck, i hope this helps :)</em>

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letter C I'm not sure to my answer but hope it can hrlp

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