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3 years ago

What is the device used to measure a potential difference in a circuit called?

Physics

2 answers:

kvasek [131]3 years ago

8 0

A voltmeter is the instrument used to measure a potential difference between two points in an electric circuit

Romashka-Z-Leto [24]3 years ago

4 0

The potential difference between two points in a circuit is
sometimes called the 'voltage' because its unit of measure
is the volt. This is a big part of the reason why a voltmeter
is the device that's used to measure it.

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A circular coil that has =130 turns and a radius of =11.5 cm lies in a magnetic field that has a magnitude of 0=0.0725 T directe

Levart [38]

I think is the half of 130

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3 years ago

Water flows over a section of Niagara Falls at rate of 1.1×10^6 kg/s and falls 49.4 m. How much power is generated by the fallin

DerKrebs [107]

Answer:

The power generated is = 5.33×10⁸ Watt.

Explanation:

Power: Power can be defined as the time rate of doing work. The S.I unit of power is Watt(W).

Mathematically,

Power (P) = Work done/time or Energy/time

P = mgh/t............................... Equation 1

P = δgh............................. Equation 2

Where δ = fall rate, g = acceleration due to gravity, h = height.

Given: δ = 1.1×10⁶ kg/s, h = 49.4 m g = 9.81 m/s²

Substituting these values into equation 2

P = 1.1×10⁶×49.4×9.81

P = 533.08×10⁶

P = 5.33×10⁸ Watt.

Thus the power generated is = 5.33×10⁸ Watt.

5 0

3 years ago

Where is the energy in a glucose molecule stored?

Semmy [17]

Answer:

Energy is stored in the bonds between atoms

4 0

3 years ago

An Airbus A350 is initially moving down the runway at 6.0 m/s preparing for takeoff. The pilot pulls on the throttle so that the

alexdok [17]

Answer:

t=67.7s

Explanation:

From this question we know that:

Vo = 6m/s

a = 1.8 m/s2

D = 1500m

And we also know that:

$X=V_{o}*t + \frac{a*t^{2}}{2}$ Replacing the known values:

$1500=6t+0.9*t^{2}$ Solving for t we get 2 possible answers:

t1 = -44.3s and t2 = 67.7s Since negative time represents an instant before the beginning of the movement, t1 is discarded. So, the final answer is:

t = 67.7s

8 0

3 years ago

A key falls from a bridge that is 32 m above the water. It falls directly into a model boat, moving with constant velocity, that

FinnZ [79.3K]

Answer:

Speed of the boat, v = 4.31 m/s

Explanation:

Given that,

Height of the bridge, h = 32 m

The model boat is 11 m from the point of impact when the key was released, d = 11 m

Firstly, we will find the time needed for the boat to get in this position using second equation of motion as :

$s=ut+\dfrac{1}{2}at^2$

Here, u = 0 and a = g

$t=\sqrt{\dfrac{2s}{g}}$

$t=\sqrt{\dfrac{2\times 32}{9.8}}$

t = 2.55 seconds

Let v is the speed of the boat. It can be calculated as :

$v=\dfrac{d}{t}$

$v=\dfrac{11\ m}{2.55\ s}$

v = 4.31 m/s

So, the speed of the boat is 4.31 m/s. Hence, this is the required solution.

3 0

3 years ago