How do you know when to rewrite square trinomials and difference of squares as separate factors
1 answer:
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Answer: There is sufficient evidence to conclude that the proportion of agenda-less meetings is greater than 45%.
Step-by-step explanation:
Given:
The p-value for this hypothesis test is 0.025.
The level of significance is α=0.05
As p-value< α ∵0.025< 0.05
[if p-value< α , we reject ]
then, we reject the null hypothesis.
i.e. We have sufficient evidence to support the alternative hypothesis.
Hence, the correct statement is : There is sufficient evidence to conclude that the proportion of agenda-less meetings is greater than 45%.
Answer:
3.30185 σ
8.7636
Step-by-step explanation:
the fromula for 100(1-α)% confidence (two sided) for σ is
√(η-1)*s^2/x^2_α/2,V σ
√(η-1)*s^2/x^2_(1-α/2,V) ∴ (v=n+1)
now data given is n = 12 and s=5.2 mg
for 99% CI ,α=0.05 and (n-1)=9 degree of freedom
from chi- square table x^2_(0.025,9)=19.02 ; x_(0.975,9)=2.7
substitute them in above expression we get
3.30185 σ
8.7636