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musickatia [10]
2 years ago
14

What is the molar mass of Ca(CIO4)2

Chemistry
2 answers:
AleksAgata [21]2 years ago
8 0

The molar mass of Ca(ClO4)2 is 239.1 g/mol.



podryga [215]2 years ago
5 0

Answer:

238.9792 g/mol

Explanation:

I just took the text

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Jessica has 12.7 moles of a compound for an experiment. How many particles of the compound does she have?
guajiro [1.7K]

Answer:

Number of moles is defined as the ratio of given mass in g to the molar mass.The mathematical expression is given as:

Number of moles  =Number of moles of compound  = 12.7 moles (given)As, 1 mole of any compound is equal to  particles.

where,    is Avogadro number. Formula for calculating particles is given by:

where, N =  number of particles, n = number of moles and  is Avogadro number.

Put the values,=  or  Hence, number of particles of the compound is equal to

Explanation:

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3 years ago
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Select all that apply. Using your periodic table of the elements which chemical symbols indicate an element?
tatuchka [14]

Answer:

O, I, Ca

Explanation:

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3 years ago
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musickatia [10]

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2 years ago
The solubility of nitrogen gas at 25 degrees C and 1 atm is 6.8 x 10^(-4) mol/L. If the partial pressure of nitrogen gas in air
Zolol [24]

Answer:

5.2 x 10⁻⁴ M.

Explanation:

  • The relationship between gas pressure and the  concentration of dissolved gas is given by  Henry’s law:

<em>P = kC</em>

where P is the partial pressure of the gaseous  solute above the solution.

k is a constant (Henry’s constant).

C is the concentration of the dissolved gas.

  • At two different pressures, there is two different concentrations of dissolved gases and is expressed in a relation as:

<em>P₁C₂ = P₂C₁,</em>

P₁ = 1.0 atm, C₁ = 6.8 x 10⁻⁴ mol/L.

P₂ = 0.76 atm, C₂ = ??? mol/L.

<em>∴ C₂ = (P₂C₁)/P₁ =</em> (0.76 atm)(6.8 x 10⁻⁴ mol/L)/(1.0 atm) = <em>5.168 x 10⁻⁴ mol/L ≅ 5.2 x 10⁻⁴ M.</em>

5 0
2 years ago
Consider the chemical equation. CuCl2 + 2NaNO3 mc023-1.jpg Cu(NO3)2 + 2NaCl What is the percent yield of NaCl if 31.0 g of CuCl2
lana [24]
CuCl2 + 2NaNO3 ---->  Cu(NO3)2 + 2NaCl

using molar masses:-
Theoretical yields:-
63.54 + 2(35.45) g  of CuCl2  produces  2(22.98 + 35.45) g of NaCl
    134.44  g .................................................... 116.86 g
       31.0 g ....................................................31.0 * 116.86 /134.44=26.95g  
 
 So percentage yield is 21.2* 100 / 26.95    =  78.7%  to nearest tenth                                                                                                              


5 0
3 years ago
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