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Dominik [7]
3 years ago
5

Calculate the density of a material that has a mass of 56.6 g and a volume of 17.2 cm

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
4 0

Answer:

d = 3.29 g/cm³

Explanation:

Given data:

Density of material = ?

Mass of material = 56.6 g

Volume of material = 17.2 cm³

Solution:

Formula;

d = m/v

d = density

m = mass

v = volume

by putting values,

d = 56.6 g/ 17.2 cm³

d = 3.29 g/cm³

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Lemur [1.5K]
Yes ...................................
5 0
3 years ago
A 0.245-L flask contains 0.467 mol co2 at 159 °c. Calculate the pressure using the ideal gas law.
lubasha [3.4K]

Answer:

Pressure, P = 67.57 atm

Explanation:

<u>Given the following data;</u>

  • Volume = 0.245 L
  • Number of moles = 0.467 moles
  • Temperature = 159°C
  • Ideal gas constant, R = 0.08206 L·atm/mol·K

<u>Conversion:</u>

We would convert the value of the temperature in Celsius to Kelvin.

T = 273 + °C

T = 273 + 159

T = 432 Kelvin

To find the pressure of the gas, we would use the ideal gas law;

PV = nRT

Where;

  • P is the pressure.
  • V is the volume.
  • n is the number of moles of substance.
  • R is the ideal gas constant.
  • T is the temperature.

Making P the subject of formula, we have;

P = \frac {nRT}{V}

Substituting into the formula, we have;

P = \frac {0.467*0.08206*432}{0.245}

P = \frac {16.5551}{0.245}

<em>Pressure, P = 67.57 atm</em>

4 0
3 years ago
The elements lithium and oxygen react explosively to form lithium oxide,Li2O. how many moles of lithium oxide will form if 4.37
anygoal [31]

From the equation,

4 mole of lithium produces 2 mole of lithium oxide

4.37 mol of lithium produces (4.37÷4)x2 mol of lithium oxide

5 0
3 years ago
The half-life of krypton-91 (91Kr) is 10 s. At time t = 0 a heavy canister contains 7 g of this radioactive gas. (a) Find a func
Vlad1618 [11]

Answer:

misteri Cell ini quest ia half-life of beauty of misteri best, of Cell can't answer =

Explanation:

\sqrt[ \geqslant  { { | \geqslant  | \geqslant  \sqrt[ \gamma \% log_{ \tan( \sqrt[ < \pi \sqrt[ | \geqslant  \sqrt[ <  \leqslant  |x| ]{y} |  \times \frac{?}{?} ]{?} ]{?} ) }(?) ]{?} | | }^{2} }^{?} ]{ \sqrt[ <  \gamma  log_{ \frac{ | \geqslant y \sqrt[ |x \sqrt{ |?| } | ]{?} | }{?} }(?) ]{?} }

5 0
3 years ago
5. There is no water cycle where it is cold.<br> O true<br> O false
Archy [21]

Answer:

False

Explanation:

There is a water cycle wherever there is water. If it is cold, the water cycle will just be very slow.

5 0
3 years ago
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