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Nadusha1986 [10]
3 years ago
8

Rank the objects below from least to greatest momentum:

Physics
1 answer:
11111nata11111 [884]3 years ago
7 0

Answer:

The correct order of momentum from least to greatest is given as

School building < Butter fly < Book falling from table < Car travelling on highway

Explanation:

As we know that the momentum is defined as the product of mass and velocity

Here we have to compare the momentum of objects by the mass and velocity both

A car travelling down the highway

A book falling from a table

A butterfly flying through the air

The school building

out of above all car is heavy as well as moving with high speed on highway so it will have maximum momentum, then school building is heavy in mass but its speed is zero so its momentum is minimum and least

Then out of butter fly and the book the book is much heavy than butter fly so momentum of book is more than butter fly

So here correct order is

School building < Butter fly < Book falling from table < Car travelling on highway

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30

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4 years ago
Suppose the rocket in the Example was initially on a circular orbit around Earth with a period of 1.6 days. Hint (a) What is its
ruslelena [56]

Answer:

a

The orbital speed is v= 2.6*10^{3} m/s

b

The escape velocity of the rocket is  v_e= 3.72 *10^3 m/s

Explanation:

Generally angular velocity is mathematically represented as

            w = \frac{2 \pi}{T}

Where T is the period which is given as 1.6 days = 1.6 *24 *60*60 = 138240 sec

       Substituting the value

         w = \frac{2 \pi}{138240}

             = 4.54*10^ {-5} rad /sec

At the point when the rocket is on a circular orbit  

   The gravitational force =  centripetal force and this can be mathematically represented as

              \frac{GMm}{r^2} = mr w^2

Where  G is the universal gravitational constant with a value  G = 6.67*10^{-11}

            M is the mass of the earth with a constant value of M = 5.98*10^{24}kg

            r is the distance between earth and circular orbit where the rocke is found

               Making r the subject

                     r = \sqrt[3]{\frac{GM}{w^2} }

                        = \sqrt[3]{\frac{6.67*10^{-11} * 5.98*10^{24}}{(4.45*10^{-5})^2} }

                        = 5.78 *10^7 m

The orbital speed is represented mathematically as

                   v=wr

Substituting value

                  v= (5.78*10^7)(4.54*10^{-5})

                     v= 2.6*10^{3} m/s    

The escape velocity is mathematically represented as

                            v_e = \sqrt{\frac{2GM}{r} }

Substituting values

                             = \sqrt{\frac{2(6.67*10^{-11})(5.98*10^{24})}{5.78*10^7} }

                             v_e= 3.72 *10^3 m/s

7 0
4 years ago
In the chemical formula 3NH4, how many total atoms of nitrogen (N
Rus_ich [418]
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8 0
3 years ago
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defon

Answer:

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Explanation:

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The correct answer is b

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Fittoniya [83]

Answer:

A=0.80

Explanation:

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