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Nadusha1986 [10]
3 years ago
8

Rank the objects below from least to greatest momentum:

Physics
1 answer:
11111nata11111 [884]3 years ago
7 0

Answer:

The correct order of momentum from least to greatest is given as

School building < Butter fly < Book falling from table < Car travelling on highway

Explanation:

As we know that the momentum is defined as the product of mass and velocity

Here we have to compare the momentum of objects by the mass and velocity both

A car travelling down the highway

A book falling from a table

A butterfly flying through the air

The school building

out of above all car is heavy as well as moving with high speed on highway so it will have maximum momentum, then school building is heavy in mass but its speed is zero so its momentum is minimum and least

Then out of butter fly and the book the book is much heavy than butter fly so momentum of book is more than butter fly

So here correct order is

School building < Butter fly < Book falling from table < Car travelling on highway

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Glucose can have a straight chain of ______________ atoms or, more commonly, form a _____________ structure.
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Lipids and <span>Polysaccharides r the answers hoped i helped</span>
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Black widow (m=57000 g) shovels snow, holding the shovel at a 40 degree angle above the ground. If she uses a constant force of
Dima020 [189]

Answer:

She does a work of 689.44 J in the snow.

Explanation:

A force is said to do work when it alters the state of motion of a body. The work of the force on that body will be equivalent to the energy needed to move it.

In other words, Work is a form of energy transmission between bodies. In order to carry out work, a force must be exerted on a body and it must move.

The work is equal to the product of the force times the distance and the cosine of the angle that exists between the direction of the force and the direction that the moving point or object travels:

W= F*d* cos Ф

Work W is measured in joules (J), force is measured in newtons (N), and displacement in meters (m).

In this case:

  • F= 180 N
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  • Ф= 40 degrees

Replacing:

W= 180 N*5 m* cos 40

Solving:

W= 689.44 J

<u><em>She does a work of 689.44 J in the snow.</em></u>

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How many pounds of force must a guardrail’s top rail be able to withstand? A. 150 lbs. B. 200 lbs. C. 400 lbs. D. 5,000 lbs.
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A proton is projected in the positive x direction into a region of a uniform electric field E S 5 126.00 3 105 2 i^ N/C at t 5 0
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Answer:

(a). The magnitude of the acceleration of the proton is 5.74\times10^{13}\ m/s^2

(b). The initial peed of the protion is 2.83\times10^{6}\ m/s

(c). The time is 0.493\times10^{-7}\ sec.

Explanation:

Given that,

Electric field E=-6.00\times10^{5}i\ N/C

Time = 5.0 sec

Distance 7.00 cm

(a). We need to calculate the acceleration

Using formula of force

F=F_{e}

ma=qE

a=\dfrac{Eq}{m}

Where, E = electric field

m = mass of proton

q = charge of proton

Put the value into the formula

a=\dfrac{-6.00\times10^{5}\times1.6\times10^{-19}}{1.67\times10^{-27}}

a=-5.74\times10^{13}\ m/s62

The magnitude of the acceleration of the proton is 5.74\times10^{13}\ m/s^2

(b). We need to calculate the initial peed

Using equation of motion

v^2-u^2=2as

Where, s = distance

Put the value into the formula

0-u^2=2\times(-5.74\times10^{13})\times7.00\times10^{-2}

u=\sqrt{2\times5.74\times10^{13}\times7.00\times10^{-2}}

u=2834783.94

u=2.83\times10^{6}\ m/s

The initial peed of the protion is 2.83\times10^{6}\ m/s

(c). We need to calculate the time interval over which the proton comes to rest

Using formula

t=\dfrac{u}{a}

Where, u = initial velocity

a = acceleration

Put the value into the formula

t=\dfrac{2.83\times10^{6}}{5.74\times10^{13}}

t=0.493\times10^{-7}\ sec

Hence, (a). The magnitude of the acceleration of the proton is 5.74\times10^{13}\ m/s^2

(b). The initial peed of the protion is 2.83\times10^{6}\ m/s

(c). The time is 0.493\times10^{-7}\ sec.

5 0
3 years ago
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