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inessss [21]
3 years ago
10

A 30.0 mL sample of 0.200 M Ba(OH)2 is titrated with 0.100 M HCl.

Chemistry
1 answer:
Phantasy [73]3 years ago
7 0

Answer:

what's the question? is it A

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All elements have a unique atomic emission spectrum. In which of the following scenarios would this fact be most useful?
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Because unique atomic emission spectrum, analyzing the  emission spectrum you can tell the chemical composition.
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Which one of the following compounds is an example of a covalent molecule?
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How many levels of full body protective clothing are there
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5 0
3 years ago
Read 2 more answers
Show the empirical formula manganese fluoride; 59.1% Mn and 40.9% F. Fill in the subscripts on the formula below. Make sure to h
Gre4nikov [31]

Hey there!:

Given % of Mn=59.1% means 59.1 g of Mn present in 100 g of manganese fluoride.

Molar mass of Mn= 54.938 g/mol

Moles of Mn = mass / molar mass

59.1 /54.938 => 1.07 ≈ 1 mol.

and % of F=40.9% means 40.9 g of of F present in 100 g of manganese fluoride.

Molar mass of F=18.998 g/mol

Moles of F :

40.9 / 18.999 => 2.15 mol ≈ 2 mol.

The mole ratio between Mn:F=  1 : 2

Therefore the empirical formula of manganese fluoride:

=> MnF2=Mn1F2

Hope that helps!

3 0
4 years ago
Read 2 more answers
A 0.539 g sample of a metal, M, reacts completely with sulfuric acid according to the reaction M(s)+H2SO4(aq)⟶MSO4(aq)+H2(g) A v
Charra [1.4K]

Answer:

The molar mass of the metal is 54.9 g/mol.

Explanation:

When we work with gases collected over water, the total pressure (atmospheric pressure) is equal to the sum of the vapor pressure of water and the pressure of the gas.

Patm = Pwater + PH₂

PH₂ = Patm - Pwater = 1.0079 bar - 0.03167 bar = 0.9762 bar

The pressure of H₂ is:

0.9762bar.\frac{1atm}{1.013bar} =0.9637atm

The absolute temperature is:

K = °C + 273 = 25°C + 273 = 298 K

We can calculate the moles of H₂ using the ideal gas equation.

P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{0.9637atm \times 0.249L }{(0.08206atm.L/mol.K)\times298K} =9.81 \times 10^{-3} mol

Let's consider the following balanced equation.

M(s) + H₂SO₄(aq) ⟶ MSO₄(aq) + H₂(g)

The molar ratio of M:H₂ is 1:1. So, 9.81  × 10⁻³ moles of M reacted. The molar mass of the metal is:

\frac{0.539g}{9.81 \times 10^{-3} mol} =54.9g/mol

4 0
4 years ago
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