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2 years ago

Approximately how many formula units of Co2(HPO4)3 are found in 175. g of hydrogenphosphate ion?

Chemistry

1 answer:

marshall27 [118]2 years ago

4 0

Answer:

This question lacks options, the options are:

A. 2.89 x 1022

B. 8.66 x 1022

C. 3.66 x 1023

D. 1.10 x 1024

E. 3.29 x 1024

The answer is C. 3.66 × 10^23

Explanation:

In the chemical compound given as follows: Co2(HPO4)3, hydrogenphosphate ion is (HPO4)3.

Number of moles of hydrogenphosphate ion can be calculated using the formula

mole (n) = mass (m) /molar mass (MM)

Molar mass of (HPO4)3;

{1 + 31 + 16(4)}3

= {32 + 64)3

= (96)3

= 288g/mol

mole = 175/288

mole = 0.6076

mole = 0.607mol

The formula of units of hydrogenphosphate ion can be calculated by multiplying number of moles by Avogadro's number (6.022 × 10²³)

6.022 × 10²³ × 0.607

= 3.655 × 10²³

= 3.66 × 10²³

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tensa zangetsu [6.8K]

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Putting in the values we get:

$1.8\times 10^{-5}=\frac{(0.25\times \alpha)^2}{(0.25-0.25\times \alpha)}$

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the symbol for xenon (xe) would be a part of the noble gas notation for the element antimony. cesium.

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