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allochka39001 [22]
3 years ago
5

A rocket experiences a constant force even as the amount of fuel in its fuel tanks decreases. What happens to the acceleration o

f the rocket as it runs out of fuel?
A - The acceleration decreases because the mass increases.B - The acceleration increases because the mass increases.C - The acceleration decreases because the mass decreases.D - The acceleration increases because the mass decreases.
Physics
2 answers:
prohojiy [21]3 years ago
7 0

We can answer this question by looking at Newton's second law:

F=ma

which can be rewritten as

a=\frac{F}{m}

where F is the force experienced by the rocket, m is its mass, a is its acceleration. In the rocket's case, the mass of the rocket decreases (because the fuel in the tank decreases), while the force remains constant, so the ratio F/m increases, and therefore the acceleration of the rocket increases.

Therefore, the correct answer is

D - The acceleration increases because the mass decreases.

Elanso [62]3 years ago
3 0
The correct answer is D
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A test tube of length L and cross-sectional area A is submerged in water with the open end down so that the edge of the tube is
Margaret [11]

Answer:

if we measure the change in height of the gas within the had and obtain a straight line in relation to the depth we can conclude that the air complies with Boye's law.

Explanation:

The air in the tube can be considered an ideal gas,

           P V = nR T

In that case we have the tube in the air where the pressure is P1 = P_atm, then we introduce the tube to the water to a depth H

For pressure the open end of the tube is

         P₂ = P_atm + ρ g H

Let's write the gas equation for the colon

            P₁ V₁ = P₂ V₂

            P_atm V₁ = (P_atm + ρ g H) V₂

             V₂ = V₁    P_atm / (P_atm + ρ g h)

If the air obeys Boyle's law e; volume within the had must decrease due to the increase in pressure, if we measure the change in height of the gas within the had and obtain a straight line in relation to the depth we can conclude that the air complies with Boye's law.

The main assumption is that the temperature during the experiment does not change

6 0
2 years ago
All of the following are factors affecting flow rate except what?
faust18 [17]

Answer:

c. Vessel side holes

Explanation:

  • The "Poiseuille formula" which is given by \\\begin{aligned} \small Q& =  \small \frac{\pi r^4}{8 \eta}.\frac{\Delta P}{\Delta L}\\\end{aligned} describes the volumetric flow rate (\small Q) through tubular sections.
  • Here, \Delta P,\,\, \Delta L,\,\, r,\,\, \eta represent the injection pressure difference, the length of the section, the radius of the section and the viscosity index of the fluid that flows through the section respectively.
  • With this, one can confirm that all the factors except the vessel side holes affect the flow rate.
  • Side holes, however, are a factor that could give a measure of how much volume would flow to a particular location. In such a situation the flow rate remains unchanged and one location would receive a lower volume (not the whole) as some volume would spill out at the side holes.

#SPJ4

5 0
1 year ago
¿Cómo es el movimiento uniforme de los pedales de una bicicleta con respeto a la tierra y con respecto al ciclista?
Nastasia [14]
Respecto al ciclista
6 0
3 years ago
The more cores in a golf ball, the more ________ that will be created.
Free_Kalibri [48]
<span>The answer is spin<span>.

The more cores in a golf ball, the more </span>spin<span> that will be created.

Depending on how many layers or cores there are in a golf ball, the number of spins that it will generate when a shot is made increases accordingly.</span></span>
8 0
3 years ago
A dolphin jumps out of the water. As it falls back down it a clerated at a rate of -9,8m/s^2 for 0.8 seconds of free fall. To ca
Anettt [7]

Answer:

0.196 m

Explanation:

Given in the question that,

time taken by the dolphin to go back to water = 0.2 sec

To solve the question we will use Newton's Law of motion

<h3>S = ut + 0.5(a)t²</h3>

here S is distance covered

u is initial speed

a = acceleration due to gravity

t = time taken

Plug value in the equation above

S = 0(0.2) + 0.5(-9.8)(0.2)²

S = 0.5(-9.8)(0.2)²

S = -0.196 m

Negative sign represent direction

(Assuming that dolphin have a vertical straight jump not a projectile motion)

4 0
3 years ago
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