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allochka39001 [22]
3 years ago
5

A rocket experiences a constant force even as the amount of fuel in its fuel tanks decreases. What happens to the acceleration o

f the rocket as it runs out of fuel?
A - The acceleration decreases because the mass increases.B - The acceleration increases because the mass increases.C - The acceleration decreases because the mass decreases.D - The acceleration increases because the mass decreases.
Physics
2 answers:
prohojiy [21]3 years ago
7 0

We can answer this question by looking at Newton's second law:

F=ma

which can be rewritten as

a=\frac{F}{m}

where F is the force experienced by the rocket, m is its mass, a is its acceleration. In the rocket's case, the mass of the rocket decreases (because the fuel in the tank decreases), while the force remains constant, so the ratio F/m increases, and therefore the acceleration of the rocket increases.

Therefore, the correct answer is

D - The acceleration increases because the mass decreases.

Elanso [62]3 years ago
3 0
The correct answer is D
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What happens if you add additional,solid NaCl after the maximum has been reached?
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Section 1: Experimental Overview
Luden [163]

Answer:

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Explanation:

7 0
3 years ago
The circuit has a 3 volt EMF and two ohm resistors. How much power in watts does this circuit draw? A) 4.5 , B) 24, C) 1.13 D) 2
dlinn [17]

Answer:

P = 4.5 watts

Explanation:

Given that,

EMF of the circuit, E = 3 volt

The resistance  of the resistors, R = 2 ohms

We need to find the power of this circuit. The relation between power, emf and resistance is given by the formula as follows :

P=\dfrac{V^2}{R}

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5 0
3 years ago
Suppose a plane accelerates from rest for 30 s, achieving a takeoff speed of 80 m/s after traveling a distance of 1200 m down th
Margaret [11]

Answer:

300 m

Explanation:

The train accelerate from the rest so u = 0 m/sec

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The distance traveled by first plane = 1200 m

We know the equation of motion S=ut+\frac{1}{2}at^2 where s is distance a is acceleration and u is initial velocity

Using this equation for first plane 1200=0\times 30+\frac{1}{2}a30^2

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As the acceleration is same for both the plane so a for second plane will be 2.67 \frac{m}{sec^2}

The another equation of motion is v^2=u^2+2as using this equation for second plane 40^2=0+2\times 2.67\times s

s = 300 m

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3 years ago
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