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CaHeK987 [17]
2 years ago
14

What elements are in SC14

Chemistry
1 answer:
zheka24 [161]2 years ago
5 0
Element Symbol Atomic weight # Mass percent
Sulfur S 32.065 1 16.0153
Carbon C 12.0107 14 83.9847
You might be interested in
In a mixture of He, O, and N, gases He exerts a partial pressure of 15.22 mm Hg and
gayaneshka [121]

Answer:

P(N)  = 38.48 mmHg

Explanation:

Given data:

Partial pressure of He = 15.22 mmHg

Partial pressure of O = 35.21 mmHg

Partial pressure of N = ?

Total pressure = 88.91 mmHg

Solution:

According to Dalton law of partial pressure,

The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.

Mathematical expression:

P(total) = P₁ + P₂ + P₃+ ............+Pₙ

Now we will solve this  problem by using this law.

P(total) = P(He) + P(O) + P(N)

88.91 mmHg = 15.22 mmHg + 35.21 mmHg + P(N)

88.91 mmHg = 50.43 mmHg + P(N)

P(N)  = 88.91 mmHg  - 50.43 mmHg

P(N)  = 38.48 mmHg

7 0
3 years ago
What does quantization refer to?
coldgirl [10]

Answer:

Having a specific set of possible values

6 0
1 year ago
Which of these are physical changes in matter chech all that apply
serious [3.7K]

Answer:

a pencil being sharpened

freezing water

boiling water

Explanation:

a physical change doesn't change the chemical structure of an object. That is why the other 2 are wrong

6 0
3 years ago
Read 2 more answers
If aluminum is diffused into a thick slice of silicon with no previous aluminum in it at a temperature of 1100˚C for 8 hours, wh
RideAnS [48]

Answer:

8.354 nanometers

Explanation:

To treat a diffusive process in function of time and distance we need to solve  2nd Ficks Law. This a partial differential equation, with certain condition the solution looks like this:

\frac{C_{s}-C{x}}{C_{s}-C_{o}}=erf(x/2\sqrt{D*t})

Where Cs is the concentration in the surface of the solid

Cx is the concentration at certain deep X

Co is the initial concentration of solute in the solid

and erf is the error function

Then we solve right side,

\frac{C_{s}-C{x}}{C_{s}-C_{o}}=\frac{1018atoms/cm3-1016atoms/cm3}{1018atoms/cm3}=0.001964

And we need to look up the inverse error function of 0.001964 resulting in: 0.00174055

Then we solve for x:

x=0.00174055*2*\sqrt{D*t} =0.00174055*2*\sqrt{2*10^{-12}cm^{2}/s*8h*3600s/h}=8.35464*10^{-7}cm

6 0
3 years ago
A 25.0-mL sample of 0.150 M butanoic acid is titrated with a 0.150 M NaOH solution. What is the pH before any base is added? The
hoa [83]
HA ⇄ H⁺ + A⁻ 
so:
\frac{[H^+][A^-]}{[HA]} = 1.5 x 10^{-5}
and now:
\frac{(x)(x)}{(0.150-x)} = 1.5 x 10⁻⁵
x is considered very small compared to 0.15
x² = 2.25 x 10⁻⁶
x = 1.5 x 10⁻³
So [H⁺] = 1.5 x 10⁻³
pH = - log [H⁺] = - log (1.5 x 10⁻³) = 2.83
7 0
3 years ago
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