The equation for Louis's purchase is: 
The equation for Kate's purchase is: 
The equation for Biff's purchase is: 
Step-by-step explanation:
First of all we have to define variables for each item involved in the purchase
Let x represent burger
y represent soda
z be the slice of pizza
Then
"Louis bought a burger and soda for $8"
"Kate purchased a slice of pizza and soda for $9"
"Biff purchased a burger, a slice of pizza and a soda for $13.50"
The equation for Louis's purchase is:
The equation for Kate's purchase is:
The equation for Biff's purchase is:
Keywords: Linear Equations, Variables
Learn more about Linear equations at:
#LearnwithBrainly
Answer:
1.05
Step-by-step explanation:
number starts as .105
slide the decimal over 1 space
1.05
EDF and GHL are similar. The scale factor is 1/2.
Answer:
x = 55°
Step-by-step explanation:
The sum of the 3 angles in a triangle is 180°
Subtract the sum of the 2 given angles from 180 for x
x = 180° - (75 + 50)° = 180° - 125° = 55°
Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%
