Answer:
Wavelength=75 cm.
The wavelength well remain unchanged which is 75 cm.
Explanation:
The formula which will help us to answer the question is:
V=f*λ
Where:
V is the velocity
f is the frequency of wave
λ is the wave length
Now:
λ=V/f Eq (1)
The equation show's that wavelength is independent of the amplitude but it depends on the frequency and the velocity with which wave is moving.
The wavelength well remain unchanged which is 75 cm.
Answer:
because the wavelength of electron beams is much shorter than the wavelength of visible light
Answer:
28 cm and 32 cm
Explanation:
1. The spring pendulum hangs vertically, oscillates harmonic with amplitude 2cm and angular frequency 20 rad/s. The natural length of
a spring is 30cm. What is the minimum and maximum length of the spring during the oscillation? Take g = 10m/s2.
As the amplitude is 2 cm and the natural length is 30 cm. So, it oscillates between 30 -2 = 28 cm to 30 + 2 = 32 cm.
So, the minimum length is 28 cm and the maximum length is 32 cm.
Answer:
see that the correct one is B
Explanation:
To solve this exercise let us use the kinematic relations
v² = v₀² - 2 a x
as they indicate that the car stops, therefore the final speed is yield v = 0
x = v₀² / 2a
let's calculate
x = 2²/(2 0.8)
x = 2.5 m / s²
When reviewing the answers we see that the correct one is B
Answer:
1/5 km/min
Explanation:
the formula for velocity is distance/time
so if i plug in the distance and time i get 5/25 or 1/5
Hope this helps!
