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2 years ago

If n is the energy level, the number of electrons in that energy level is

Chemistry

1 answer:

attashe74 [19]2 years ago

3 0

Answer:

I needed some free points that's why I am doing so

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Please Help! It says fill in the blanks to complete the Punnett square below to show the results of a cross between a homozygous

makkiz [27]

Answer:

Genotypes: Homozygous (GG)=50%, Heterozygous (Gg)=50%.

Phenotypes: Homozygous gray (GG)=50%, Heterozygous gray (Gg)=50% or just Gray=100%

Explanation:

Hello,

The Punnett square for this cross turns into:

$\left[\begin{array}{ccc}&G&g\\G&GG&Gg\\G&GG&Gg\end{array}\right]$

It means that the genotypes and phenotypes are:

Genotypes: Homozygous (GG)=50%, Heterozygous (Gg)=50%.

Phenotypes: Homozygous gray (GG)=50%, Heterozygous gray (Gg)=50% or just Gray=100%

Best regards.

4 0

2 years ago

What is my formula? Silver l acetate

Nutka1998 [239]

Answer:

Ag(I)C2H3O2 ....................

Silver only has a single valence value (+1) so you really don't need to put the (I) in the chemical formula.

7 0

2 years ago

What is the Kelvin temperature for 30°C? 130 K 30 K 273 K 293 K 303 K

pishuonlain [190]

The answer is 303 K, to find K you have to add 273 to the °C

8 0

3 years ago

The free energy of an electrochemical cell is given by the equation:

Nuetrik [128]

To obtain the number of moles of electrons, we need to multiply both sides by 1/FE.

<h3>What is electrochemical cell?</h3>

The electrochemical cell is a cell in which energy is produced by chemical reactions which are spontaneous. We can obtain the free energy of an electrochemical cell using the equation; ΔG=-nFE

To make n the subject of the formula, we need to multiply both sides by 1/FE as follows;

$\frac{dG}{FE} = n$ .

Learn more about electrochemical cell: brainly.com/question/4592165

7 0

2 years ago

Mercury and its compounds have uses from fillings for teeth (as a mixture with silver, copper, and tin) to the production of chl

Y_Kistochka [10]

Answer:

0.6410g of HgS (mercury (II) sulfide) are formed

Explanation:

First you should write the balanced chemical equation, so we have:

$Na_{2}S+Hg(NO_{3})_{2}=HgS+_{2}NaNO_{3}$

Where:

$Na_{2}S$ is the formula for the sodium sulfide

$Hg(NO_{3})_{2}$ is the formula for the mercury (II) nitrate

$HgS$ is the formula for the mercury (II) sulfide

and

$NaNO_{3}$ is the formula for the sodium nitrate

Then you should calculate the amount of each substance in each solution, so:

- For the $Na_{2}S$ :

$Molarity=\frac{n_{Na_{2}S}}{Lofsolution}$

$n_{Na_{2}S}=0.048M*0.236L$

$n_{Na_{2}S}=0.010856$ moles of $Na_{2}S$

- For the $Hg(NO_{3})_{2}$ :

$Molarity=\frac{n_{Hg(NO_{3})_{2}}}{Lofsolution}$

$n_{Hg(NO_{3})_{2}}=0.019M*0.145L$

$n_{Hg(NO_{3})_{2}}=0.002755$ moles of $Na_{2}S$

As the quantity of $Hg(NO_{3})_{2}$ is smaller than the quantity of $Na_{2}S$ . The $Hg(NO_{3})_{2}$ is the limiting reagent and you should work with this quantity, so we have:

$0.002755molesHg(NO_{3})_{2}*\frac{1molHgS}{1molHg(NO_{3})_{2}}=0.002755$ moles of HgS

And as the molar mass of the HgS is $232.66\frac{g}{mol}$ you can calculate the mass of HgS that is produced:

$0.002755molesHgS*\frac{232.66gHgS}{1molHgS}=0.6410g$ HgS

3 0

3 years ago