Answer:
x^2-4x+3
Step-by-step explanation:
Since the zeroes of the quadratic are 1 and 3, we can set up an equation in factored form:
(x-1)(x-3)
=x^2-4x+3
We can further check that this is the right answer by evaluating it at the vertex:
(2)^2-4*2+3=-1
Since that corresponds to the graph, the answer is x^2-4x+3
Hey!
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LCD stands for Lowest Common Denominator.
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Explanation:
So let's say we have the equation 1/9 * 16/27
We want to find the LCD of both fractions. To find the LCD of both fractions find a the lowest common denominator in both fractions.
In this equation the lowest common denominator is 27 because 9 can go in 27 and 27 can go into itself. Se basically 27 is the lowest possibly common denominator both fractions can get to.
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Hope This Helped! Good Luck ;)
Answer:
A.) gf(x) = 3x^2 + 12x + 9
B.) g'(x) = 2
Step-by-step explanation:
A.) The two given functions are:
f(x) = (x + 2)^2 and g(x) = 3(x - 1)
Open the bracket of the two functions
f(x) = (x + 2)^2
f(x) = x^2 + 2x + 2x + 4
f(x) = x^2 + 4x + 4
and
g(x) = 3(x - 1)
g(x) = 3x - 3
To find gf(x), substitute f(x) for x in g(x)
gf(x) = 3( x^2 + 4x + 4 ) - 3
gf(x) = 3x^2 + 12x + 12 - 3
gf(x) = 3x^2 + 12x + 9
Where
a = 3, b = 12, c = 9
B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)
To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula
Y = 3x + 3
X = 3y + 3
Make y the subject of formula
3y = x - 3
Y = x/3 - 3/3
Y = x/3 - 1
Therefore, g'(x) = x/3 - 1
For g'(12), substitute 12 for x in g' (x)
g'(x) = 12/4 - 1
g'(x) = 3 - 1
g'(x) = 2.
