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3 years ago

The speed of a car during a trip is represented in the graph. Compare distance and displacement at four hours into the trip.

Physics

2 answers:

mezya [45]3 years ago

7 0

Answer:

The answer to your question is: D.

Explanation:

Distance refers to the amount of space between two points, it is a scalar quantity.

Displacement refers to the space between two points, measure from the minimum path linking them, it is a vector quantity.

I'm not agree with these answers, because the total distance is approximately 500km.

A) The distance traveled is 300 km. This answer is not correct.

B) Distance is 300 km and displacement is 0 km. This answer is not correct because the displacement is also 500 km.

C) Distance is 300 km/hour and displacement is 300 km. 300 km/h is a measure of speed not of distance, this option is wrong.

D) Both distance traveled and displacement are 300 km. I think this is the correct answer because distance and displacement measure the same. but I think both measure 500 km.

den301095 [7]3 years ago

5 0

Answer:

A) The distance traveled is 300 km.

Explanation:

Since the graph represents the distance time graph so we don't have any idea about the path length of the car.

So here we can not comment about the displacement of the motion of the car

so here we can see from the graph that

at t = 0 the position of the car is x = 0

now when car will reach at t = 4 hour

the distance of the car is

d = 300 km

so we can say that distance covered by the car will be

d = 300 km

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Two subway stops are separated by 1210 m. If a subway train accelerates at 1.30 m/s2 from rest through the first half of the dis

solong [7]

Answer:

Part 1) Time of travel equals 61 seconds

Part 2) Maximum speed equals 39.66 m/s.

Explanation:

The final speed of the train when it completes half of it's journey is given by third equation of kinematics as

$v^{2}=u^2+2as$

where

'v' is the final speed

'u' is initial speed

'a' is acceleration of the body

's' is the distance covered

Applying the given values we get

$v^2=0+2\times 1.30\times \frac{1210}{2}\\\\v^{2}=1573\\\\\therefore v=39.66m/s$

Now the time taken to attain the above velocity can be calculated by the first equation of kinematics as

$v=u+at\\\\v=0+1.30\times t\\\\\therefore t=\frac{39.66}{1.30}=30.51seconds$

Since the deceleration is same as acceleration hence the time to stop in the same distance shall be equal to the time taken to accelerate the first half of distance

Thus total time of journey equals $T=2\times 30.51\approx61seconds$

Part b)

the maximum speed is reached at the point when the train ends it's acceleration thus the maximum speed reached by the train equals $39.66m/s$

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3 years ago

CAN SOMEONE PLEASE HELP ME

s2008m [1.1K]

The answer should be B

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If the air pressure is doubled, the speed of sound

Tom [10]

it remains unchanged

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3 years ago

Which sentence describes Newton's first law?

Marrrta [24]

$\Large{\red{\bf{\blue{\dag} Answer:-}}}$

Newton's First Law of Motion :

An object stays in rest or in uniform motion unless and until compelled by an external unbalanced force . This is also known as " Law of Inertia " .

Here this statement is best represented by the statement : Unbalanced forces cause an object to move. [ option c ]

More to know :-

Newton's 3 laws of motion :-

Newton's First Law of Motion :-

It states that an object stays in rest or in uniform motion unless and until compelled by an external unbalanced force . This is also known as " Law of Inertia " .

Ex - (i) We tend to fall backwards while standing in the bus , when it starts suddenly.

(ii) We tend to fall forward while standing in the bus , when it stops suddenly.

Newton's Second Law of Motion :-

It states that the rate of change of momentum is directly proportional to the applied force in the direction of the force . That is ∆p $\propto$ Force .

Ex - (i) When we push car & a truck with same force the car will have Greater acceleration due to less mass . (Imaginary case ).

(ii) We feel easy to push a empty cart than a full cart .

Newton's Third Law of Motion :-

It states that every action has equal and opposite reaction .

Ex - (i) We are able to walk on ground due to Newton's third law of motion .

(ii) When we push wall it also applies equal and opposite force .

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3 years ago

What force is required to accelerate a 1,000 kg car 5 m/s2?

marysya [2.9K]

F = ma
F = (1000 kg)•(5 m/s^2)
F = 5000 N

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