Answer:
The original length of the specimen 
Explanation:
Original diameter
= 30 mm
Final diameter
= 30.04 mm
Change in diameter Δd = 0.04 mm
Final length
= 105.20 mm
Elastic modulus E = 65.5 G pa = 65.5 ×
M pa
Shear modulus G = 25.4 G pa = 25.4 ×
M pa
We know that the relation between the shear modulus & elastic modulus is given by



This is the value of possion's ratio.
We know that the possion's ratio is given by


0.00476

Final length
= 105.2 m
Original length


This is the original length of the specimen.
Answer:
138.9 °C
Explanation:
The datum of quality is saying to us that liquid water is in equilibrium with steam. Saturated water table gives information about this liquid-vapour equilibrium. In figure attached, it can be seen that at 350 kPa of pressure (or 3.5 bar) equilibrium temperature is 138.9 °C
Answer:
The flexural strength of a specimen is = 78.3 M pa
Explanation:
Given data
Height = depth = 5 mm
Width = 10 mm
Length L = 45 mm
Load = 290 N
The flexural strength of a specimen is given by


78.3 M pa
Therefore the flexural strength of a specimen is = 78.3 M pa
Based on the information, both technician A and technician B are correct.
<h3>How to depict the information?</h3>
From the information given, Technician A says that mechanical shifting controls can wear out over time.
Technician B says that vacuum control rubber diaphragms can deteriorate over time.
In this case, both technicians are correct as the information depicted is true.
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