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pychu [463]
4 years ago
8

Estimate the theoretical fracture strength (in MPa) of a brittle material if it is known that fracture occurs by the propagation

of an elliptically shaped surface crack of length 0.25 mm that has a tip radius of curvature of 0.004 mm when a stress of 1060 MPa is applied.

Engineering
1 answer:
Annette [7]4 years ago
6 0

Answer:

σ =20700 MPa

Explanation:

Answer is in the following attachment

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Recall from an earlier lecture that the relationship between the current through an inductor and the voltage across it is given
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Answer: Current = 2A

Explanation:

Inductor L = 10mH

E.m.f = 1 V

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V = Ldi/dt

di/dt = V/ L

di/dt = 1/10×10^-3

di/dt = 100

di = 100dt

Integrate both sides

I = 100(t1 - to)

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4 Error-Correcting Polynomials (a) Alice has a length 8 message to Bob. There are 2 communication channels available. When n pac
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(m_{1}, m_{2}, m_{3}) = (3, -6, 3)

<u>Explanation:</u>

Given data,

p=m_{1} x^{2}+m_{2} x+m_{3}

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0(P(0)), 1(P(1)), 2(P(2)), 3(P(3)), 4(P(4))

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(0,3) (1,0) (2,3) (3,0) (4,3)

P(0) = 3

P(1) = 0

P(2) = 3

P(3) = 0

P(4) = 3

The given equation is

p=m_{1} x^{2}+m_{2} x+m_{3}

Solution:

p(0)=m_{1}(0)+m_{2}(0)+m_{3} = 3

m_{3} = 3

p(1)=m_{1}+m_{2}+m_{3}=0

m_{1} + m_{2} = - 3

m_{2} = -3 -m_{1}

p(2)=4 m_{1}+2 m_{2}+m_{3} = 3

4 m_{1}+2 m_{2} = 0

2 m_{1}+m_{2}=0

P(3)=9 m_{1}+3 m_{2}+m_{3}  = 0

3 m_{1}+m_{2}+3=0

P(4)=16 m_{1}+4 m_{2}+m_{3} = 3

4 m_{1}+m_{2} = 0

From P(1) and P(2)

m_{2} = -3 -m_{1}

2 m_{1}+m_{2}=0

2 m_{1}-3-m_{1}=0

-3 + m_{1}  = 0

m_{1} = 3

m_{2} = -6

(m_{1}, m_{2}, m_{3}) = (3, -6, 3)

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3 years ago
Technician A says that spot welding arms may be made of copper alloy. Technician B says that spot welding arms may be made of al
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Answer:

Technician A is correct

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