Answer:
208 Joules
Explanation:
The radius of the circular path the charge moves, r = 26 m
The magnetic force acting on the charge particle, F = 16 N
Centripetal force, 
= m·v²/r
Kinetic energy, K.E. = (1/2)·m·v²
Where;
m = The mass of the charged particle
v = The velocity of the charged particle
r = The radius of the path of the charged particle
Whereby the magnetic force acting on the charge particle = The centripetal force, we have;
F = = m·v²/r = 16 N
(1/2) × r × = (1/2) × r × m·v²/r = (1/2)·m·v² = K.E.
∴ (1/2) × r × = (1/2) × 26 m × 16 N = = (1/2)·m·v² = K.E.
∴ 208 Joules = K.E.
The kinetic energy of an particle moving in the circular path, K.E. = 208 Joules.
Answer:
That people are motivated by a series of five universal needs.
Explanation:
6 hours long, give or take a few minutes, you need to wait to see them arranged in a horizontal line if, at 8 pm, you see that the pointer stars of the big dipper and the star Polaris are arranged in a vertical line.
<h3 /><h3>What do you mean by pointer star?</h3>
The two prominent stars in Ursa Major known as the Pointer Stars can be utilized to locate Polaris, the North Star. The Big Dipper asterism includes the two stars Dubhe and Merak (Alpha and Beta Ursae Majoris). They trace the bowl of the Dipper's exterior. The direction of the North Star is indicated with a line that runs from Merak via Dubhe. Because it identifies the location of the celestial north pole, Polaris is significant in navigation. While other stars and constellations seem to revolve around it, the star is constantly found in the same location in the sky throughout the year.
To learn more about Polaris, Visit:
brainly.com/question/1130377
#SPJ4
Answer:
65.01 N
Explanation:
N = 9
m1 = 68 kg
m2 = 73 kg
F1 = 1350 N towards left
F2 = 1365 N towards right
Fleft = N x F1 = 9 x 1350 = 12150 N
FRight = N x F2 = 9 x 1365 = 12285 N
Fnet = Fright - Fleft = 12285 - 12150 = 135 N right
Let a be the acceleration
a = Fnet / N(m1 + m2) = 135 / 9(68 + 73) = 0.1064 m/s^2
Let T be the tension in the rope
By the Newton's second law
Fnet - T = 9 m2 x a
135 - T = 9 x 73 x 0.1064
T = 65.01 N
