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bezimeni [28]
3 years ago
8

What is the frequency of a wave having a period equal to 18 seconds ​

Physics
1 answer:
Ivanshal [37]3 years ago
3 0

Explanation:

The time taken by a wave crest to travel a distance equal to the length of wave is known as wave period.

The relation between wave period and frequency is as follows.

T = \frac{1}{f}T=

f

1

where, T = time period

f = frequency

It is given that wave period is 18 seconds. Therefore, calculate the wave period as follows.

T = \frac{1}{f}T=

f

1

or, f = \frac{1}{T}f=

T

1

= \frac{1}{18 sec}

18sec

1

= 0.055 per second (1cycle per second = 1 Hertz)

or, f = 5.5 \times 10^{-2} hertz5.5×10 −2 hertz

<h3>Thus, we can conclude that the frequency of the wave is 5.5 \times 10^{-2} hertz5.5×10 −2 hertz .</h3>
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The density of gold is 19.3 g/cm^3. what is the mass of 24 cm^3 of gold?
maw [93]

Mass = Density * Volume

Density = 19.3 g/cm³

Volume = 24 cm³

Mass = Density * Volume = 19.3 g/cm³ * 24 cm³ = 463.2 g

Mass = 463.2 g

3 0
3 years ago
Calculate the total force on the Earth due to Venus, Jupiter, and Saturn, assuming all four planets are in a line. The masses ar
Furkat [3]
You need to consider the following:
Me (mass of Earth) = 5.98 x 10^24 kg 
<span>Ms (mass of Sun) = 1.99 x 10^30 kg </span>
<span>G = 6.67 x 10^-11 N </span>
<span>
Formula:
 F = G * M1M2/r^2 
</span><span>The ratio FT/F = 4.02x10^-4 / 14.8
 = 2.72x10^-5 
</span><span>
Since,
1/2.72x10^-5 = 36800
The fraction ratio is  1/36800
</span>= <span>9.56x10^17 N</span>
3 0
2 years ago
Read 2 more answers
A car from rest moves a distance s(m) in t second, where s=3t³+t²/4 determine(i)the initial acceleration of the car (ii)the acce
Sunny_sXe [5.5K]

Answer:

0.5 , 54.5

Explanation:

for acceleration we should derivate the equation 2 times

x=3t³+t²/4

v=9t²+t/2

a=18t+1/2

a(0)=0.5

a(3)=54.5

8 0
3 years ago
The force exerted on the tires of a car that directly accelerate it along a road is exerted by the
azamat

The force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.

<h3>What is force?</h3>

Force is defined as the product of mass and acceleration of an object.

Friction is defined as the force that resists the movement of an object over another.

Therefore, the force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.

Learn more about force here:

brainly.com/question/12970081

#SPJ12

7 0
1 year ago
A UHF television loop antenna has a diameter of 11 cm. The magnetic field of a TV signal is normal to the plane of the loop and,
Doss [256]

Answer:

-0.00152 V

Explanation:

Parameters given:

Diameter of the loop = 11 cm = 0.11m

Rate of change of magnetic field, dB/dt = 0.16 T/s

Radius of the loop = 0.055m

The area of the loop will be:

A = pi * r²

A = 3.142 * 0.055²

A = 0.0095 m²

The EMF induced in a loop of wire due to the presence of a changing magnetic field, dB, in a time interval, dt, is given as:

EMF = - N * A * dB/dt

In this case, there's only one loop, so N = 1.

Therefore:

EMF = -1 * 0.0095 * 0.16

EMF = -0.00152 V

The negative sign indicates that the current flowing through the loop acts opposite to the change in the magnetic field.

7 0
3 years ago
Read 2 more answers
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