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kolezko [41]
3 years ago
5

46.0 mL sample of gas at 28.0°C and 748 torr. What volume would this gas sample occupy at stp?

Chemistry
1 answer:
andreyandreev [35.5K]3 years ago
7 0

Answer:

2

Explanation:

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Which Cl isotope should we use to get the atomic mass of the element Cl?
Sati [7]

Answer:

i think it's B CI-35 only

Explanation:

hope this helps

5 0
3 years ago
You notice that every time you place butter on your stack of freshly made pancakes, the butter melts.
valentina_108 [34]

Answer:

Heat lost by the pancake = Heat gained by butter

Explanation:

Because energy is always conserved, this process involves the loss of energy by one substance which is gained by another.

The pancakes were freshly made, so they are hot; having the required energy to melt the butter placed on them. The butter absorbs heat from the pancakes which is equal to or greater than its melting point. Thus, the butter melts due to the heat absorbed.

Therefore,

Heat lost by the pancakes = Heat gained by butter

7 0
4 years ago
you are given an unknown gaseous binary compound. when 10.0g of the compound isburned in excess oxygen, 16.3g of water is produc
Flauer [41]
Since the compound has 1.38 time that of oxygen gas at the same conditions of temperature and pressure, we have the relationship:
MW/MWoxygen = 1.38
MW = 44.16

Since there is water formed during the reaction, the formula of the compound must be:
XaHb
where a and b are the coefficients of each element.

If the compound reactions with oxygen forming water and an oxide of the element X, the combustion reaction must be:
XaHb + ((2a + (b/2))/2) O2 = a (XO2) + (b/2)(H2O)
Using dimensional analysis:
10 (1/44.16) (b/2 / 1) (18) = 16.3
Solving for b:
b = 8

The compound now is XaH8. Most probably, the compound is C3H8 since it has a molecular formula of 44 and it reacts with O2 to form water and CO2.
5 0
4 years ago
8. True or False: There are some exceptions to the rule.... organisms such as a protist called a
ankoles [38]

There are some exceptions to the rule organisms such as a protist called a  euglena can be both heterotrophic and autotrophic. This is a true statement.

Explanation:

  • Euglena is a large genus of unicellular protists: they have both plant and animal characteristics
  • Photoautotrophs include protists that have chloroplasts, such as Spirogyra. Heterotrophs get their energy by consuming other organisms. Other protists can get their energy both from photosynthesis and from external energy sources
  • All live in water and move by means of a flag ellum. This is an animal characteristic. Most have chloroplasts, which are characteristic of algae and plants
  • Euglena is photosynthetic in the presence of sunlight i.e autotrophic, when deprived of sunlight they behave like heterotrophs by predating on other smaller organisms.
  • Most species of Euglena have photosynthesizing chloroplasts within the body of the cell, which enable them to feed by autotrophy, like plants. They can also take nourishment heterotrophically, like animals.

6 0
3 years ago
You have a 150mL sample of an aqueous solution at 25C. It contains 15.2mg of an unknown nonelectrolyte compound. If the solution
Serga [27]

The molar mass of the compound:

If the solution has an osmotic pressure of 8.44 torr, then the molar mass of the unknown non-electrolyte is 223.14 g.

What is osmosis?

  • Osmosis is defined as the flow of solvent molecules through semi-permeable membrane.
  • Osmotic pressure is the pressure applied to stop the flow of solvent molecules.
  • It is a colligative property that means osmotic pressure depends on the number of solute particles .

Therefore,

πV=inRT  ( for electrolytes)

Where,   π= Osmotic pressure

i = Van 't Hoff factor

n= moles

R= Gaseous constant = 62.363577 L torr mol^{-1}K^{-1}

T= Temperature

V= Volume of solution

Given:

T= 298K

V= 150 mL= 0.150 L

Given mass of unknown electrolyte= 15.2 mg = 15.2 x  10^{-3} g

Osmotic pressure= 8.44 torr

Molar mass= ?

For non-electrolytes:

πV = n RT

πV=\frac{m}{M}RT

Calculations:

Putting the given values in the formula:

8.44 x 0.150 =15.2 x 10^{-3}/ M x 62.36 x 298

1.266 = 282.5/M

M = 282.5/1.266

M = 223.14 g

Therefore,

The molar mass of the unknown non-electrolyte is 223.14g.

Learn more about Osmotic pressure here,

brainly.com/question/13680877

#SPJ4

7 0
2 years ago
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