(6 x 10^2) ÷ (3x 10^-5)
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the numbers are x=58 & x+2=60 , i.e. 58 and 60 .
<u>Step-by-step explanation:</u>
Here we have , Consecutive integers are 1,2,3,4 and so on. Consecutive even integers are 2,4,6,8 and so on. The sum of an integer and twice the next consecutive even integer is 178. We need to Write and solve an equation to find the two integers. Let's find out:
Let the integer be x , and the next consecutive even integer be x+2 .Now , According to question , The sum of an integer and twice the next consecutive even integer is 178 i.e.
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Therefore , the numbers are x=58 & x+2=60 , i.e. 58 and 60 .