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PSYCHO15rus [73]
3 years ago
8

What includes a distance and a direction? A. Displacement B. Velocity C. Speed D. Acceleration

Physics
2 answers:
iren [92.7K]3 years ago
7 0

hi <3

the correct option would be A. displacement. displacement is distance in a direction

hope this helps :)

alina1380 [7]3 years ago
5 0

Answer:

The reason is simple. Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement. Put another way, speed is a scalar value, while velocity is a vector.

Explanation:

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What causes resistance in an electric circuit? How is resistance measured?
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Resistance can be caused by specific resistance tools, like resistors, or loads (the part of the component that uses the electricity) like a light bulb or a speaker. Resistance is measured in ohms and can be measured by a multimeter.
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4. A vehicle
Gnom [1K]

Answer:

Average acceleration, a=2.77\ m/s^2

Explanation:

Given that,

Initial velocity, u = 0 km/h

Final velocity, v = 100 km/h = 27.77 m/s

Time, t = 10 s

We need to find the average acceleration of the vehicle. It is given by the change in velocity divided by time. Som,

a=\dfrac{v-u}{t}\\\\a=\dfrac{27.77-0}{10}\\\\a=2.77\ m/s^2

So, its average acceleration is 2.77\ m/s^2.

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4 years ago
What is the need for satellite communication elaborate
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The high frequency radio waves used for telecommunications links travel by line of sight and so are obstructed by the curve of the Earth. The purpose of communications satellites is to relay the signal around the curve of the Earth allowing communication between widely separated geographical points.

Explanation:

hope it helps!!

4 0
3 years ago
Atoms of which pair of elements will form ionic bonds in a compound?
lys-0071 [83]

Answer:

The answer D ...............

6 0
3 years ago
A space station sounds an alert signal at time intervals of 1.00 h . Spaceships A and B pass the station, both moving at 0.400c0
balandron [24]

Answer:

a)  Time interval between signals according to an observer on spaceship A  = 1.09h

b)  Time interval between signals according to an observer on spaceship B = 1.09h

c)The speed of A relative to the station to measure a time interval of 2.00h = 2.6 * 10⁸ m/s

Explanation:

a) Time interval between signals according to an observer on spaceship A

Initial time intervals for the alert signal, Δt₀ = 1.00h

The speed of spaceship A, v = 0.400c

The formula for the time interval is given by

Δt = ∆t₀ /√(1-(v/c)² )

Δt = 1 / √(1-(0.4c/c)² )

Δt = 1 / √(1-(0.4)²

Δt = 1.09 h

b) The intervals between signals according to an observer on spaceship A and B are equal because both spaceships are moving at the same speed.

Therefore, the time interval between signals according to an observer on B is Δt = 1.09 h

c) The speed of A relative to the station to measure a time interval of 2.00h

Δt = ∆t₀ /√(1-(v/c)² )

2 = 1 /√(1-(v/c)² )

√(1-(v/c)² ) = 0.5

1-(v/c)² = 0.25

0.75 = (v/c)²

v/c = 0.866

v = 0.866c

v = 0.866 * 3 * 10⁸

v = 2.6 * 10⁸ m/s

7 0
3 years ago
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