<u>Answer:</u> The substance that produces fewest particles is 
<u>Explanation:</u>
Ionization reaction is defined as the reaction in which an ionic compound dissociates into its ions when dissolved in aqueous solution.
Covalent compounds do not dissociate into ions when dissolved in aqueous solution.
For the given options:
- <u>Option 1:</u> Sodium nitrate
The chemical formula of sodium nitrate is 
The ionization reaction for the given compound follows:

This produces in total of 2 ions.
- <u>Option 2:</u>

The given compound is a covalent compound and do not dissociate into its ions. It remains as such as a single unit.
- <u>Option 3:</u>

The chemical name for the given compound is potassium sulfate.
The ionization reaction for the given compound follows:

This produces in total of 3 ions.
- <u>Option 4:</u> Sodium phosphate
The chemical formula of sodium phosphate is 
The ionization reaction for the given compound follows:

This produces in total of 4 ions.
Hence, the substance that produces fewest particles is 
Answer:
C.
Explanation:
The entropy (S) is the measure of the randomness of a system, and ΔS = Sfinal - Sinitial. As higher is the disorder of the system, as higher is the entropy.
A. When KCl is fractionated in power, there'll be more portions of it, so, the disorder must be higher, then ΔS is positive.
B. As higher is the temperature, higher is the kinetic energy of the system, and because of that, the disorder is also higher, so ΔS is positive.
C. The decrease in the volume (compression) decreases the distance between the molecules, so the system will be more organized, then ΔS is negative.
D. The volume before the mixing will be higher, and the ethanol will dissociate, so it will be more particles, the disorder will increase, and ΔS is positive.
E. Sgas > Sliquid > Ssolid because of the disorder of the molecules, then ΔS is positive.
Answer:
Compound A and compound B are constitutional isomers with molecular formula C3H7Cl.
When compound A is treated with sodium methoxide, a substitution reaction predominates. When compound B is treated with sodium methoxide, an elimination reaction predominates.
Explanation:
Constitutional isomers are the one which differs in the structural formula.
When compound A is treated with sodium methoxide, a substitution reaction predominates.
That means sodium methoxide is a strong base and a strong nucleophile.
But when it reacts with primary alkyl halides it forms a substitution product and when it reacts with secondary alkyl halide it forms mostly elimination product.
The reaction and the structures of A and B are shown below:
I think D?? I apologize if not-check in other answers to be sure ^^