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2 years ago

Dimensional analysis can only be used for time, distance, mass, speed, volume, and chemical quantities.

1 answer:

5 0

Dimensional analysis can only be used for time, distance, mass, speed, volume, and chemical quantities: False.

<h3>What is dimensional analysis?</h3>

A dimensional analysis can be defined as an analysis of the relationships that exist between different physical quantities by identifying their fundamental (base) quantities, especially for the purpose of inferences.

Dimensional analysis is also referred to as unit-factor method or factor-label method and it is typically used to convert a different type of unit to another.

Generally, dimensional analysis can only be used for the following physical quantities:

Time

Distance

Mass

Volume

Speed

In conclusion, a dimensional analysis cannot be used for chemical quantities such as a mole i.e it has no dimensional formula.

Read more on dimensional analysis here: brainly.com/question/24514347

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Answer:

Option (E) is correct

Explanation:

Solubility equilibrium of $Pb(IO_{3})_{2}$ is given as follows-

$Pb(IO_{3})_{2}\rightleftharpoons Pb^{2+}+2IO_{3}^{-}$

Hence, if solubility of $Pb(IO_{3})_{2}$ is S (M) then-

$[Pb^{2+}]=S(M)$ and $[IO_{3}^{-}]=2S(M)$

Where species under third bracket represent equilibrium concentrations

So, solubility product of $Pb(IO_{3})_{2}$ , $K_{sp}=[Pb^{2+}][IO_{3}^{-}]^{2}$

Here, $[Pb^{2+}]=S(M)=5.0\times 10^{-5}M$

So, $[IO_{3}^{-}]=2S(M)=(2\times 5.0\times 10^{-5})M=1.0\times 10^{-4}M$

So, $K_{sp}=(5.0\times 10^{-5})\times (1.0\times 10^{-4})^{2}=5.0\times 10^{-13}$

Hence option (E) is correct

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