I think it B I’m not sure
I think it consumes 0.000278 energy
If Resistors are in series= The equivalent is the sum.
E.g R1 and R2 in series, R = R1 + R2.
If in Parallel, equivalent is Product/sum.
E.g If R1 and R2 in parallel, R = (R1*R2)/(R1+R2)
1.) 60 is parallel with 40 and both are then in series with 20.
60//40 = (60*40)/(60+40) = 2400/100 = 24
Now the 24 is in series with the 20
R = 24 + 20 = 44 ohms.
2.) 80 is in series with 40 and both are then in parallel with 40.
Solving the series, R = 80 + 40 =120.
Parallel: 120//40 = (120*40)/(120+40) = 4800/160 = 30
Equivalent Resistance = 30 ohms.
3.) 100 is in parallel with 100 and both are then in series with the parallel of 50 and 50.
The 1st parallel = (100*100)/(100+100) = 10000/200 = 50
The 2nd parallel = (50*50)/(50+50) = 2500/100 = 25.
Solving the series = 50 + 25 =75 ohms.
Cheers.
<h2>
Hey There!</h2><h2>
_____________________________________</h2><h2>
Answer:</h2>
<h2>
_____________________________________</h2><h3>
DATA:</h3>
Range = R = 78m
Initial Velocity = 
= 30m/s
Angle(theta) = ?
<h2>_____________________________________</h2><h3>SOLUTION:</h3>
The Range is given by,
<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h2 />
In hydrosphere, the parameter surface temperatures does not change from low latitude to high.
Answer: Option B
<u>Explanation:</u>
Hydrosphere is made with all available water on earth, sea, planets and lakes. Its role is to sustain water various life and maintaining ecosystems. Water is present in high percentage on the earth's.
Comparing surface temperatures and lower temperatures in high latitude areas, lower sea surface temperatures found at high latitudes. In the deeper ocean, the water temperature is similar to the surface temperature, keeping the curve vertically. Hence, there is no rapid changes in the temperature with depth (remains constant).
