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balu736 [363]
3 years ago
7

Supposing d(t) is known to have value D,

Physics
1 answer:
creativ13 [48]3 years ago
5 0

Answer:

  • The procedure is: solve the quadratic equation for t.

Explanation:

This question assumes uniformly accelerated motion, for which the distance d a particle travels in time t is given by the general equation:

  • d(t)=d_0+v_0t+at^2/2

That is a quadratic equation, where the independent variable is the time t.

Thus, the procedure that will find the time t at which the distance value is known to be D is to solve the quadratic equation for t.

To solve it you start by changing the equation to the general form of the quadratic equations, rearranging the terms:

  • (a/2)t^2+v_0t+(d_0-D)=0

Some times that equation may be solved by factoring, and always it can be solved by using the quadratic formula:

  • t=\frac{-b+/-\sqrt{b^2-4ac} }{2a}

Where:

a=-a/2\\ \\ b=v_0\\ \\ c=d_0-D

That may have two solutions. Some times one of the solution makes no physical sense (for example time cannot be negative) but others the two solutions are valid.

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Let the mass of the person be m. Total momentum is conserved (because the exterior forces on the system are balanced), especially the component in the vertical direction.

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A certain car traveling in a straight line path has a velocity of +10.0 m/s at some instant. after 3.00 s, its velocity is +6.00
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A 0.25 kg skeet (clay target) is fired at an angle of 30 degrees to the horizon with a speed of 25 m/s. When it reaches the maxi
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Answer:

6.51 m and 37.13 m

Explanation:

from the question we were given

mass of skeet = 0.25 kg

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angle = 30 degrees to the horizon

mass of pellet = 15 g

speed of pellet = 2000 m/s

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Vx = 25 cos 30 = 21.65

Vy = 25 sin 30 = 12.5

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V = U + (a x t)

where V = final velocity, U = initial velocity , a = acceleration, t = time and s = distance

-25 sin 30 = 25 sin 30 + (-9.8 x t)

-12.5 = 12.5 - 9.8 t

t = 2.55 s

also

V^2 = U^2 + 2as  ( s = vertical distance and V = 0 )

0 = (25 sin 30)^2 + 2 x (-9.8) x Y

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the distance traveled without the pellet hitting the skeet can be gotten using distance = speed x time

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applying the conservation of linear momentum

on the x axis : (Ms x Us) + (Mp x Up) = (Ms x Vx) + (Mp x Vx)  ...equation 1

on the y axis :   (Ms x Us) + (Mp x Up) = (Ms x Vy) + (Mp x Vy) ...equation 2

(0.25 x 25 cos 30) + 0 = (0.25 +0.015) Vx

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now V^2 = U^2 + 2 as

 0 = 11.3^2 + (2 x (-9.8) x s)

s = 6.51 m                          

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s = ut + 1/2 at^2

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