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Anarel [89]
3 years ago
6

A rocket, blasting into space, accelerates at 2 m/s^2 for 20 seconds. What is its speed at the end of 20 seconds?​

Physics
1 answer:
OLEGan [10]3 years ago
4 0

Answer:

  Acceleration  =  (change in speed)  /  (time for the change)

Change in speed = (ending speed) - (beginning speed)

                           =     (3,600 mi/hr) - ( 0 )

                           =       3,600 mi/hr

                           =     same as  1 mile/second.

Acceleration  =  (1 mi/sec) / (10 sec)

                     =     0.1 mi/sec² .

But 1 mile = 5,280 ft,

so

                      0.1 mi/s²  =  528 ft/s²          

Explanation:

have a great day

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Part of the plant that isresponsible for the transport of water from the roots to the leaves​
nydimaria [60]

Answer:

if you mean *responsible* for the transport of water from the roots to leaves is Xylem

8 0
3 years ago
Zamir and Talia raced through a maze. Zamir walked 2 m north, 2 m east, 4 m south, 2 m east, 4 m north, 2 m east, 3 m south, 4 m
Alja [10]

Answer : Zamir's displacement and Talia's displacement is equal.

Explanation :

Displacement is explained to be the changing position of an object.

Zamir covers total distance 27 m and Talia covers total distance 19 m but  Zamir's initial and final position and Talia's initial and final position is same.

So, we can say that Zamir's displacement and Talia's displacement is equal.

6 0
3 years ago
Read 2 more answers
The maximum wavelength that an electromagnetic wave can have and still eject electrons from a metal surface is 542 nm. What is t
Veseljchak [2.6K]

Answer:

2.295 eV

Explanation:

maximum wavelength, λ = 542 nm = 542 x 10^-9 m

The work function of the metal is defined as the minimum amount of energy falling on the metal so that the photo electrons just ejects the surface of metal.

W_{o}=\frac{hc}{\lambda }

where, h is the Plank's constant and c be the speed of light

h = 6.634 x 10^-34 Js

c = 3 x 10^8 m/s

W_{o}=\frac{6.634\times 10^{-34}\times 3\times 10^{8}}{542\times10^{-9} }

W_{o}=3.67\times 10^{-19} J=\frac{3.67\times 10^{-19}}{1.6\times 10^{-19}} eV

Wo = 2.295 eV

Thus, the work function of this metal is 2.295 eV.

5 0
3 years ago
If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front o
andrezito [222]
The answer is

18 / x = 12 / 4 
12x = 72
x = 6mm
4 0
3 years ago
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A tuning fork labeled 392 Hz has the tip of each of its two prongsvibrating with an amplitude of 0.600mma) What is the maximum s
DanielleElmas [232]

a) 1.48 m/s

The tuning fork is moving by simple harmonic motion: so, the maximum speed of the tip of the prong is related to the frequency and the amplitude by

v_{max}=\omega A

where

v_{max} is the maximum speed

\omega is the angular frequency

A is the amplitude

For the tuning fork in the problem, we have

\omega=2\pi f=2 \pi(392 Hz)=2462 rad/s, where f is the frequency

A=0.600 mm=6\cdot 10^{-4} m is the amplitude

Therefore, the maximum speed is

v_{max}=(2462 rad/s)(6\cdot 10^{-4}m)=1.48 m/s

b)  3.0\cdot 10^{-5} J

The fly's maximum kinetic energy is given by

K=\frac{1}{2}mv_{max}^2

where

m=0.0270 g=2.7\cdot 10^{-5} kg is the mass of the fly

v_{max}=1.48 m/s is the maximum speed

Substituting into the equation, we find

K=\frac{1}{2}(2.7\cdot 10^{-5}kg)(1.48 m/s)^2=3.0\cdot 10^{-5} J

7 0
3 years ago
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