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In this experiment, we will be performing a titration with a buret. place the steps in order. 1. record the ph when 0.0 ml of na

77julia77 [94]

I am guessing that your solutions of HCl and of NaOH have approximately the same concentrations. Then the equivalence point will occur at pH 7 near 25 mL NaOH.

The steps are already in the correct order.

1. Record the pH when you have added 0 mL of NaOH to your beaker containing 25 mL of HCl and 25 mL of deionized water.

2. Record the pH of your partially neutralized HCl solution when you have added 5.00 mL of NaOH from the buret.

3. Record the pH of your partially neutralized HCl solution when you have added 10.00 mL, 15.00 mL and 20.00 mL of NaOH.

4. Record the NaOH of your partially neutralized HCl solution when you have added 21.00 mL, 22.00 mL, 23.00 mL and 24.00 mL of NaOH.

5. Add NaOH one drop at a time until you reach a pH of 7.00, then record the volume of NaOH added from the buret ( at about 25 mL).

6. Record the pH of your basic HCl-NaOH solution when you have added 26.00 mL, 27.00 mL, 28.00 mL, 29.00 mL and 30.00 mL of NaOH.

7. Record the pH of your basic HCl-NaOH solution when you have added 35.00 mL, 40.00 mL, 45.00 mL and 50.00 mL of NaOH from your 50mL buret.

4 0

3 years ago

Which of the following is not a property of water? Hydrogen bonding causes a high surface tension. Hydrogen bonds exist only in

vlada-n [284]

Answer:

water can dissolve ionic and polar molecules.

6 0

3 years ago

The frequency of a given region of the electromagnetic spectrum ranges from

quester [9]

The ranges given are 4 × 10^14 to 7.5 × 10^14 Hz. At these frequencies, visible light type of waves are found in this region. This occurs at a wavelength of 400 - 700 nanometers and a color of violet through red. Outside this range, the naked eye cannot see the waves.

5 0

3 years ago

How much heat energy is needed to heat 250 g of water from 200C to its boiling point and then completely vaporize it?

alexandr1967 [171]

Answer: 40.66kJ/mol.

Explanation:Assuming that pressure is equal to Explanation:Assuming that pressure is equal to 1 atm Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at 100

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at 100∘

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at 100∘C

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at 100∘C .

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at 100∘C .The amount of heat needed to allow one mole of water to undergo this phase change is called the enthalpy change of vaporization,

nge of vaporization, Δ

nge of vaporization, ΔH

nge of vaporization, ΔHvap

nge of vaporization, ΔHvap .

nge of vaporization, ΔHvap .For water at

nge of vaporization, ΔHvap .For water at 100

nge of vaporization, ΔHvap .For water at 100∘

nge of vaporization, ΔHvap .For water at 100∘C

nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal to

nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal toΔ

nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal toΔH

nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal toΔHvap

nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal toΔHvap=

nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal toΔHvap=40.66 kJ/mol

8 0

3 years ago

You are given 600 grams of sodium chloride (NaCl), but you are planning to purify the substance and extract just the sodium. How

Eddi Din [679]

Answer:

236.02 grams of Na is produced by 600g of NaCl.

Explanation:

NaCl --> Na+Cl-

to find the number of moles NaCl has, divide the grams over the molar mass which is 600/58.44

number of moles of nacl= 10.2 moles

then turn moles back to grams which is moles x molar mass

10.2 moles x 22.9 mass

= 236.02 grams

4 0

3 years ago

Heyyyyyyyyyyyyyyyyyyyyy wusup? how yall doing