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Elena L [17]
3 years ago
11

A bag weighing 20 N is pushed horizontally a distance of 35 m across a

Physics
1 answer:
topjm [15]3 years ago
6 0

Answer:

350J

Explanation:

Given parameters:

Weight of bag  = 20N

Distance moved horizontally  = 35m

Force applied  = 10N

Unknown:

Work done on the bag  = ?

Solution:

Work done is the force applied to move a body through given distance.

  Work done  = Force applied x distance

So;

 Work done  = 10 x 35  = 350J

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3 years ago
Please help &amp; actually answer thank you :)
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Answer:

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2 years ago
Rotational dynamics about a fixed axis: A person pushes on a small doorknob with a force of 5.00 N perpendicular to the surface
FrozenT [24]

Answer:

I = 2 kgm^2

Explanation:

In order to calculate the moment of inertia of the door, about the hinges, you use the following formula:

\tau=I\alpha     (1)

I: moment of inertia of the door

α: angular acceleration of the door = 2.00 rad/s^2

τ: torque exerted on the door

You can calculate the torque by using the information about the Force exerted on the door, and the distance to the hinges. You use the following formula:

\tau=Fd        (2)

F: force = 5.00 N

d: distance to the hinges = 0.800 m

You replace the equation (2) into the equation (1), and you solve for α:

Fd=I\alpha\\\\I=\frac{Fd}{\alpha}

Finally, you replace the values of all parameters in the previous equation for I:

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The moment of inertia of the door around the hinges is 2 kgm^2

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3 years ago
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