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lina2011 [118]
3 years ago
7

What is the name of the force that keeps the planets and other celestial bodies orbiting around the sun

Physics
2 answers:
Paladinen [302]3 years ago
8 0

Answer:

gravity

Explanation:

zhenek [66]3 years ago
6 0
Gravity is the name of the force that keeps the planets in orbit
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A steel ball with mass m is suspended from the ceiling at the bottom end of a light, 17.0-m-long rope. The ball swings back and
iogann1982 [59]

Answer:

1. 18.25 m/s

2. 0 m/s

Explanation:

1.So the centripetal acceleration of the ball at this lowest point must be, taking gravity into account

a_c = \frac{T - mg}{m} = \frac{3mg - mg}{m} = 2g

The speed at this point would then be

v^2 = a_c r = 2gr = 2*9.8*17 = 333.2

v = \sqrt{333.2} = 18.25 m/s

2. Similarly, if T = mg, then the centripetal acceleration must be

a_c = \frac{T - mg}{m} = \frac{mg - mg}{m} = 0

As the ball has no centripetal acceleration, its speed must also be 0 as well.

6 0
4 years ago
Which numbers on the ph scale indicate an acid
KiRa [710]

Answer:

0 - 6.9 --> Acidic

Explanation:

4 0
3 years ago
During the power stroke energy released by combustion generates the force that:_______.
Inessa05 [86]

Explanation:

An IC engines means an Internal Combustion engine. Here, the combustion takes place in side a chamber or a cylinder internally, hence it is known as internal combustion engine.

Combustion is the process where oxygen reacts with the fuel and it burns to produce a large amount of force and heat. In each revolution of the crank, the engine creates a power stroke when the piston goes from the bottom dead center to the top dead center.

During each power stroke, the energy released forces the piston down and the crankshaft is rotated.

8 0
3 years ago
Please help!!! I have a physics exam tomorrow and I just can't wrap my head around this one!
Ainat [17]

The total electrostatic force on charge A is 28 \mu N

Explanation:

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

Here we have three positively charged particles A,B and C, located at the following positions:

x_A = 0\\x_B = 10 m\\x_C = 20 m

The magnitudes of the three charges are:

q_A = q_B = q_C = 0.5 \mu C = 0.5\cdot 10^{-6}C

The force exerted by B on A is to the left (because the force between two positive charges is repulsive), and the force exerted by C on A is also to the left (also repulsive). Therefore, the net force on A is just the sum of the two forces exerted by charges B and C:

F_A = F_{BA} + F_{CA} = k\frac{q_B q_A}{(x_B-x_A)^2}+k\frac{q_C q_A}{(x_C-x_A)^2}=\\=(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(10)^2}+(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(20)^2}=2.8\cdot 10^{-5} N = 28 \mu N

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

3 0
3 years ago
Learning Goal: To practice Problem-Solving Strategy 19.1 Work in Ideal-gas Processes. A cylinder with initial volume VVV contain
Leokris [45]

Answer:

The work done on the gas is equal to the area under the curve pv diagram w = area of triangle = 1/2 (base)(height) = 1/2 (BC)(Ac) = 1/2 (3v - v)(3p - p) = 1/2 (9 vp - 3 vp - 3vp + vp) = 4 vp/2 W = 2 vp

Check attachment for the diagrammatic representation

5 0
4 years ago
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