Ask question

Ask question

All categories

3 years ago

7

What is the name of the force that keeps the planets and other celestial bodies orbiting around the sun

2 answers:

Paladinen [302]3 years ago

8 0

Answer:

gravity

Explanation:

zhenek [66]3 years ago

6 0

Gravity is the name of the force that keeps the planets in orbit

You might be interested in

Which of the following activities will most likely help Anthony manage his stress levels

dangina [55]

Answer:

Sports, friends, family, a girlfriend or someone he can talk to ,

Explanation:

3 0

3 years ago

EXPERTS/ACE and people that wanna help 4 sure only!

oee [108]

To do this you want to solve for one variable at a time. So we want to cancel out a variable. Lets cancel x. I will multiply the first equation by the number 4 to get 4y=4x-16.
Now lets solve equation 2 for y, giving
-3y=-4x+3 now add equation 1 to equation 2
Y =-13
Now plug that back in to either
-13=x-4
X=-9
So the answer is (-9,-13)

7 0

3 years ago

In 1909 Robert Millikan was the first to find the charge of an electron in his now-famous oil drop experiment. In the experiment

mrs_skeptik [129]

Answer:

$1.49\cdot 10^{-17}C$

Explanation:

The oil drop remains stationary when the electric force on it and the gravitational force are balanced, so we have:

$F_E = F_G\\qE = mg$

where

q is the charge of the oil drop

E is the electric field strength

m is the mass of the drop

g is the acceleration due to gravity

here we have

$E=1\cdot 10^6 N/C$

$m=1.51837\cdot 10^{-12} kg$

$g=9.8 m/s^2$

So the charge of the drop is

$q=\frac{mg}{E}=\frac{(1.51837\cdot 10^{-12} kg)(9.8 m/s^2)}{1\cdot 10^6 N/C}=1.49\cdot 10^{-17}C$

8 0

3 years ago

A train slows its speed from 52 kilometers per hour to 46 kilometers per hour in 0.04 hour. What is the acceleration o the train

BigorU [14]

Answer: here you go i have to put 20 letters in so just ignore this and look at the link.

3 0

3 years ago

The Sun has a mass of 1.99x10^30 kg and a radius of 6.96x10^8 m. Calculate the acceleration due to gravity, in meters per second

just olya [345]

Answer:

$g=274\ m/s^2$

Explanation:

Mass of the Sun, $M=1.99\times 10^{30}\ kg$

The radius of the Sun, $r=6.96\times 10^8\ m$

We need to find the acceleration due to gravity on the surface of the Sun. It is given by the formula as follows :

$g=\dfrac{GM}{r^2}\\\\g=\dfrac{6.67\times 10^{-11}\times 1.99\times 10^{30}}{(6.96\times 10^8)^2}\\\\g=274\ m/s^2$

So, the value of acceleration due to gravity on the Sun is $274\ m/s^2$ .

8 0

3 years ago