Answer:
a. 
b. K = 192.9
c. Products are favored.
Explanation:
Hello!
a. In this case, according to the unbalanced chemical reaction we need to balance HCl as shown below:

In order to reach 2 hydrogen and chlorine atoms at both sides.
b. Here, given the concentrations at equilibrium and the following equilibrium expression, we have:
![K=\frac{[HCl]^2}{[H_2][Cl_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BHCl%5D%5E2%7D%7B%5BH_2%5D%5BCl_2%5D%7D)
Therefore, we plug in the data to obtain:

c. Finally, we infer that since K>>1 the forward reaction towards products is favored.
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Answer:
Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.
Explanation:
The benzene ring in itself does not easily undergo electrophilic substitution reaction. Some groups activate or deactivate the benzene ring towards electrophilic substitution reactions.
-NO2 ia a highly deactivating substituent therefore, Friedel-Crafts alkylation of nitrobenzene does not take place under any conditions.
This reaction scheme is therefore flawed because Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.
Answer:
The answer is B an open system allows energy and mass to move in and out of it
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Solutions 1 and 3 because they are strong acids and a strong base. <u>Option A.</u>
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Strong acids and strong bases are completely ionized in an aqueous solution. Weak acids and weak bases also ionize, but only partially and the reaction is reversible. So you know if an acid or base is strong or weak. A simple way to determine strength is to add the acid or base to water. A higher reactivity means a stronger acid or base.
One of the simplest tests to determine whether a solution is an acid or base is the litmus paper test. To do this, dip a special strip of paper so-called litmus paper into the solution and observe the color of the paper. Litmus paper turns red in acidic solutions and blue in basic solutions. Sodium hydroxide is the strongest base because it completely dissociates to form sodium and hydroxide ions. These hydroxide ions are further treated with hydrogen ions by an acid to completely ionize the hydrogen ions.
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This is a symbiotic relationship called commensalism if the tree root is the only one to benefit.