Answer:
a. Electric Energy
b. Light Energy
c. Thermal Energy
Explanation:
a. When a lamp is turned on by means of a switch, electric energy is usually used, since that is the form of energy that is generated when there is a potential difference between two points, which allows to establish an electric current, that electric current travels through the wires up to the bulb of the lamp
b. In this case a case of light energy is presented since that is the energy transported by the light and that is manifested on the matter in different ways, one of them is to remove the electrons from the metals. This is what usually happens in some types of light bulbs, that when the displacement of the electrons is promoted, a beam of light is generated.
c. The last case is a case of thermal energy, since this energy is that expressed as the total kinetic energy resulting from the random movements of atoms and molecules. This was what could happen in case b, when the beam of light was generated. This energy is released in the form of heat, and may present high temperatures.
69.9%
Explanation:
To find the mass percentage of iron in the compound in Fe₂O₃, we would go ahead to express the given molar mass of the iron to that of the compound.
Mass percentage =
x 100
Molar mass of Fe = 55.85g/mol
Molar mass of O = 16g/mol
Molar mass of Fe₂O₃ = 2(55.85) + 3(16) = 159.7g/mol
Mass percentage =
= 69.94% = 69.9%
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If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).
<h3>
What is base dissociation constant?
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The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.
The dissociation reaction of hydrogen cyanide can be given as
HCN --- (H+) + (CN-)
Given,
The value of Ka for HCN is 2.8× 10^(-9)
The correlation between base dissociation constant and acid dissociation constant is
Kw = Ka × Kb
Kw = 10^(-14)
Substituting values of Ka and Kw,
Kb = 10^(-14) /{2.8×10^(-9) }
= 3.5× 10^(-6)
Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).
DISCLAIMER: The above question have mistake. The correct question is given as
Question:
Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?
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Only one of the listed choices are correct here:
<span><em>The x-axis would change title and values.</em>
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