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marishachu [46]
3 years ago
14

What assumption is being made if scientists conclude that aspartic acid was formed by the prebiological synthesis in the passage

?
A.Aspartic acid is unstable at temperatures below 150°C.
B.All of the malic acid underwent the dehydration reaction to form fumaric/maleic acid.
C.Compound A and cyanide were available on primitive Earth.
D.The reaction between ammonia and fumaric acid was catalyzed by the presence of water.
Chemistry
2 answers:
miss Akunina [59]3 years ago
8 0

Answer:

A....

Explanation:

almond37 [142]3 years ago
6 0

Answer:

A. Aspartic acid is unstable at temperatures below 150°C.

Explanation:

Aspartic acid  is an amino acid that is used in the production of proteins within  living cells.  It contains an amino group and a carboxylic acid, and can be synthesized by the body. It is a non-essential amino acid. The prebiological formation of aspartic acid occured at a certain temperature range. It was deduced from the passage that aspartic acid is unstable at temperatures below 150°C. The transamination of oxaloacetate in the human body gives rise to the formation of aspartate which is facilitated by the enzyme, aminotransferases. Aspartate also play a major role in the formation of urea by acting as a metabolite.

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3 years ago
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What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)
nikdorinn [45]

Answer : The volume of O_2 consumed are, 0.75\times 2\times 22.4 L.

Explanation :

The balanced chemical reaction will be:

4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)

First we have to calculate the moles of Al.

\text{Moles of }Al=\frac{\text{Mass of }Al}{\text{Molar mass of }Al}

Molar mass of Al = 27 g/mole

\text{Moles of }Al=\frac{55g}{27g/mol}=2mole

Now we have to calculate the moles of O_2.

From the reaction we conclude that,

As, 4 mole of Al react with 3 moles of O_2

So, 2 mole of Al react with \frac{3}{4}\times 2=0.75\times 2 moles of O_2

Now we have to calculate the volume of O_2 consumed.

As we know that, 1 mole of substance occupies 22.4 liter volume of gas.

As, 1 mole of O_2 occupies 22.4 liter volume of O_2 gas

So, 0.75\times 2 mole of O_2 occupies 0.75\times 2\times 22.4 liter volume of O_2 gas

Therefore, the volume of O_2 consumed are, 0.75\times 2\times 22.4 L.

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3 years ago
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3 years ago
How many grams of iron oxide, Fe2O3 will be produced if 165 g of O2 gas is supplied? (follow the same steps as mol to mol, only
forsale [732]

Answer:

m_{Fe_2O_3}=549gFe_2O_3

Explanation:

Hello there!

In this case, according to the given chemical reaction for this problem about stoichiometry:

4Fe+3O_2\rightarrow 2Fe_2O_3

Whereas there is a 3:2 mole ratio of oxygen (molar mass = 32.0 g/mol) to iron (III) oxide (molar mass = 159.69 g/mol) and therefore, the correct stoichiometric setup is:

m_{Fe_2O_3}=165gO_2*\frac{1molO_2}{32.00gO_2}*\frac{2molFe_2O_3}{3molO_2} *\frac{159.69gFe_2O_3}{1molFe_2O_3}  \\\\m_{Fe_2O_3}=549gFe_2O_3

Regards!

8 0
3 years ago
Sodium carbonate can be made by heating sodium bicarbonate: 2NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g) Given that ΔH° = 128.9 kJ/m
Ad libitum [116K]

Answer:

[tex]128^{o}C[/tex]minimum temperature will the reaction become spontaneous.

Explanation:

\Delta G=\Delta H-T \Delta S

From the given,

\Delta G^{o}=33.1

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Temperature\,change=25+273=98K

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\Delta S=0.322kJ/mol.K

\Delta G=\Delta H-T \Delta S

0=128.9-T(0.322)=401K=218^{o}C

Therefore, 128^{o}Cminimum temperature will the reaction become spontaneous.

7 0
3 years ago
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