Answer:
0.44 moles
Explanation:
Given that :
A mixture of water and graphite is heated to 600 K in a 1 L container. When the system comes to equilibrium it contains 0.17 mol of H2, 0.17 mol of CO, 0.74 mol of H2O, and some graphite.
The equilibrium constant ![K_c= \dfrac{[CO][H_2]}{[H_2O]}](https://tex.z-dn.net/?f=K_c%3D%20%20%5Cdfrac%7B%5BCO%5D%5BH_2%5D%7D%7B%5BH_2O%5D%7D)
The equilibrium constant 
The equilibrium constant 
Some O2 is added to the system and a spark is applied so that the H2 reacts completely with the O2.
The equation for the reaction is :
Total mole of water now = 0.74+0.17
Total mole of water now = 0.91 moles
Again:
![0.03905 = \dfrac{[0.17+x][x]}{[0.91 -x]}](https://tex.z-dn.net/?f=0.03905%20%3D%20%20%5Cdfrac%7B%5B0.17%2Bx%5D%5Bx%5D%7D%7B%5B0.91%20-x%5D%7D)
0.03905(0.91 -x) = (0.17 +x)(x)
0.0355355 - 0.03905x = 0.17x + x²
0.0355355 +0.13095
x -x²
x² - 0.13095
x - 0.0355355 = 0
By using quadratic formula
x = 0.265 or x = -0.134
Going by the value with the positive integer; x = 0.265 moles
Total moles of CO in the flask when the system returns to equilibrium is :
= 0.17 + x
= 0.17 + 0.265
= 0.435 moles
=0.44 moles (to two significant figures)
Answer:
They are both planets made out of gas!
They both share methane, hydrogen and helium gases!
To find the mole of a substance, you take the mass divided by the molar mass of that substance~
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Answer:
The specific heat of the sample unknown metal is approximately 0.45 J/g °C.
General Formulas and Concepts:
<u>Thermodynamics</u>
Specific Heat Formula: 
- <em>m</em> is mass (g)
- <em>c</em> is specific heat capacity (J/g °C)
- Δ<em>T</em> is the change in temperature
Explanation:
<u>Step 1: Define</u>
<em>Identify variables.</em>
<em>m</em> = 112 g
Δ<em>T</em> = 20.0 °C
<em>q</em> = 1004 J
<u>Step 2: Solve for </u><u><em>c</em></u>
- Substitute in variables [Specific Heat Formula]:
- Simplify:
- Isolate <em>c</em>:
- Round [Sig Figs]:
∴ specific heat capacity <em>c</em> is equal to around 0.45 J/g °C.
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Topic: AP Chemistry
Unit: Thermodynamics
