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3 years ago

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A mnemonic device in which phrases or poems use the first letter of each word to help a person remember the information is an ex

ample of a(n) __________.
A.
acronym
B.
rhyme
C.
list
D.
acrostic

2 answers:

Aleks04 [339]3 years ago

7 0

Answer:

D.

acrostic

Explanation:

shusha [124]3 years ago

3 0

Answer:

D. Acrostic

Explanation:

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All of the following are examples of electric current except _______.

Aleks04 [339]

<span>Electrical discharge from a charged object
is your answer</span>

4 0

3 years ago

The space shuttle orbits 310 km above the surface of the Earth.

MAVERICK [17]

Answer:

44.7 N

Explanation:

The gravitational force between the objects is given by:

$F=G\frac{mM}{r^2}$

where

G is the gravitational constant

m and M are the masses of the two objects

r is the distance between the centres of the two objects

In this problem, we have:

$m=5.0 kg$ is the mass of the sphere

$M=5.98\cdot 10^{24} kg$ is the Earth's mass

$R=6370 km$ is the Earth's radius, while h=310 km is the altitude of the sphere, so the distance of the sphere from Earth's centre is

$r=6370 km+310 km=6680 km=6.68\cdot 10^6 m$

Substituting into the equation, we find

$F=(6.67\cdot 10^{-11})\frac{(5.0 kg)(5.98\cdot 10^{24} kg)}{(6.68\cdot 10^6 m)^2}=44.7 N$

8 0

3 years ago

You are on a skateboard not moving when your friend throws you a basketball and you catch it. The 0.50kg basketball was going 5

Sidana [21]

Answer:

a. Your mass with the basketball is 55.5 kg

b. Your new velocity is 0.045 m/s

Explanation:

We first add your weight and the basketballs weight to get 55.5 kg.

Then to find b. we use the equation: v final = (m1 * v1) / (m1 +m2)

So m1 is the basketball which is 0.5 kg and v1 is 5 m/s. So the top half is (0.5 * 5)

The bottom half is just our weights added together.

7 0

2 years ago

Read 2 more answers

A player kicks a soccer ball from ground level and sends it flying at an angle of 30 degrees at a speed of 26 m/s. What is the m

Akimi4 [234]

Answer:

8.6 m

Explanation:

The motion of a soccer ball is a motion of a projectile, with a uniform motion along the horizontal (x-) direction and an accelerated motion along the vertical (y-) direction, with constant acceleration $a=g=-9.8 m/s^2$ towards the ground (we take upward as positive direction, so acceleration is negative).

The initial velocity along the vertical direction is

$v_{y0} = v_0 sin \theta = (26 m/s)(sin 30^{\circ})=13 m/s$

Now we can consider the motion along the vertical direction only. the vertical velocity at time t is given by:

$v_y(t)=v_{y0} +at$

At the point of maximum height, $v_y(t)=0$ , so we can find the time t at which the ball reaches the maximum height:

$0=v_{y0}+at\\t=-\frac{v_{y0}}{a}=-\frac{13 m/s}{-9.8 m/s^2}=1.33 s$

And now we can use the equation of motion along the y-axis to find the vertical position of the ball at t=1.33 s, which corresponds to the maximum height of the ball:

$y(t)=v_{y0}t + \frac{1}{2}at^2=(13 m/s)(1.33 s)+\frac{1}{2}(-9.8 m/s^2)(1.33 s)^2=8.6 m$

4 0

3 years ago

Determine the automobile’s braking distance from 90 km/h when it is going up a 5° incline. (Round the final value to one decimal

NeX [460]

Answer:

366 m

Explanation:

u = 90 km/h = 25 m/s,

theta = 5 degree

acceleration, a = g Sin theta = 9.8 x Sin 5 = 0.854 m/s^2

The final velocity os zero and let the braking distance be s.

Use third equation of motion

v^2 = u^2 - 2 a s

0 = 25 x 25 - 2 x 0.854 x s

s = 366 m

8 0

3 years ago