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Sati [7]
2 years ago
11

A mnemonic device in which phrases or poems use the first letter of each word to help a person remember the information is an ex

ample of a(n) __________.
A.
acronym
B.
rhyme
C.
list
D.
acrostic
Physics
2 answers:
Aleks04 [339]2 years ago
7 0

Answer:

D.

acrostic

Explanation:

shusha [124]2 years ago
3 0

Answer:

D. Acrostic

Explanation:

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Is gravity a field force
Alekssandra [29.7K]
Yes, it is because gravity is a force of attraction to the center of our planet, Earth. If we drop a pencil, the pencil will go on the floor. Gravity is pulling the pencil down. 
5 0
3 years ago
Un engrane que gira con una velocidad de 20 rad/s, es acelerado durante 5 segundos hasta alcanzar una velocidad de 35 rad/s
larisa [96]

Answer:

a) La aceleración angular es: \alpha=2\: rad/s^{2}

b) El engranaje gira 125 radianes.

c) El engranaje hara aproximadamente 20 revoluciones.

Explanation:

a)

La aceleración angular se define como:

\alpha=\frac{\Delta \omega}{\Delta t}

Donde:

  • Δω es la diferencia de velocidad angular (en otras palabras ω(final)-ω(inicial))
  • Δt es el tiempo en el que occure el cambio de velocidad angular

\alpha=\frac{35-25}{5}

\alpha=2\: rad/s^{2}

b)

El desplazamiento angular puede ser calculado usando la siguiente ecuación:

\theta=\theta_{i}+\omega_{i}t+\frac{1}{2}\alpha t^{2}

Aqui el angulo inicial es 0, por lo tanto.

\theta=20(5)+\frac{1}{2}(2)(5)^{2}

\theta=125\: rad

El engranaje gira 125 radianes.

c)

Lo que debemos hacer aquí es convertir radianes a revoluciones.

Recordemos que 2π rad = 1 rev

Entonces:

\theta=125\: rad \times \frac{1\: rev}{2\pi\: rad}=19.89\: rev

Por lo tanto el engranaje hara aproximadamente 20 revoluciones.

Espero te haya sido de ayuda!

6 0
3 years ago
Which of the following is the primary medium for beach erosion? ice gravity wind water
Fiesta28 [93]
I believe it is water that is the medium for beach erosion
3 0
3 years ago
Read 2 more answers
Starting from one oasis, a camel walks 25 km in a direction 30° south of west and then walks 30 km toward the north to a second
shepuryov [24]

Answer:

distance between both oasis ( 1 and 2) is  27.83 Km

Explanation:

let d is the distance between oasis1 and oasis 2

from figure

OC  = 25cos 30

OE = 25sin30

OE = CD

Therefore BC =  30-25sin30

distance between both oasis ( 1 and 2) is calculated by using phytogoras theorem

in\Delta BCO

OB^2 = BC^2 + OC^2

PUTTING ALL VALUE IN ABOVE EQUATION

d^2 = 930-25sin30)^2 + (25cos30)^2

d^2 = 775

d = 27.83 Km

distance between both oasis ( 1 and 2) is  27.83 Km

3 0
3 years ago
What is the effect on the force of gravity between two objects if the mass of one object doubles?
Leni [432]
Then the force will also be doubled
6 0
3 years ago
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