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3 years ago

Newton's Law of Gravity states that if the mass of one object doubles, the gravitational pull on a second object will

Physics

2 answers:

Yakvenalex [24]3 years ago

8 0

Answer:

It doubles.

If the mass of one of the objects is doubled, then the force of gravity between them is doubled. Since the gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.

OLEGan [10]3 years ago

5 0

Answer:

It will double.

Explanation:

Newton's Law of Gravity states that $F_G=\frac{Gm_1m_2}{r^{2}}$ , where G is the gravitational constant, <em>r</em> is the distance between the objects' centers, and $m_1$ and $m_2$ are the objects' masses. We just have simple math here: by doubling $m_1$ , we double the entire fraction. By doubling the entire fraction, we double the gravitational pull. Therefore, <em>Newton's Law of Gravity states that if the mass of one object doubles, the gravitational pull on a second object will </em><em>double</em><em>.</em>

I hope this helps you understand it! Have a great day, 'kay?

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A truck is moving north word at a constant speed the momentum of the car is

nataly862011 [7]

Answer:

its constant i think

Explanation:

or its stable dunno which term will they be using

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3 years ago

The kinetic energy of an object with a mass of 6.8 kg and a velocity of 5.0 m/s is J. (Report the answer to two significant figu

abruzzese [7]

Answer:

$\boxed{\sf Kinetic \ energy \ (KE) = 85 \ J}$

Given:

Mass (m) = 6.8 kg

Speed (v) = 5.0 m/s

To Find:

Kinetic energy (KE)

Explanation:

Formula:

$\boxed{ \bold{\sf KE = \frac{1}{2} m {v}^{2} }}$

Substituting values of m & v in the equation:

$\sf \implies KE = \frac{1}{2} \times 6.8 \times {5}^{2}$

$\sf \implies KE = \frac{1}{ \cancel{2}} \times \cancel{2} \times 3.4 \times 25$

$\sf \implies KE =3.4 \times 25$

$\sf \implies KE = 85 \: J$

8 0

4 years ago

Read 2 more answers

What happens if magnesium is added to hydrochloric acid (hci) in a single replacement reaction

STatiana [176]

It produces hydrogen gas

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3 years ago

An object is located 70 cm from a concave mirror with a focal length of 15 cm. What is the image

Stels [109]

(a) The distance of the image formed by the concave mirror is 19.1 cm.

(b) The image formed is diminished and real.

<h3>Image distance </h3>

The distance of the image formed by the concave mirror is calculated as follows;

1/f = 1/v + 1/u

1/v = 1/f - 1/u

1/v = 1/15 - 1/70

1/v = 0.05238

v = 1/0.05238

v = 19.1 cm

The image distance is smaller than object distance, thus the image formed is diminished and real.

Learn more about concave mirror here: brainly.com/question/13164847

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5 0

2 years ago

A hiker determines the length of a lake by listening for the echo of her shout reflected by a cliff at the far end of the lake.

ArbitrLikvidat [17]

Answer:

L = 499 m

Explanation:

If we assume that the speed of sound is constant, that travels along a straight line, and that the echo is instantaneous, we can find the total distance travelled by the sound, as follows, just applying the definition of average velocity:

$\Delta x = v_{s} * t = 343 m/s* 2.91 s = 998 m$

If we assume that the time needed to reach to the cliff, is the same used for the return travel, the length of the lake will be exactly half of the total distance calculated:

$l_{lake} = \frac{\Delta x}{2} = \frac{998m}{2} = 499 m$

The length of the lake is 499 m.

8 0

3 years ago