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Ludmilka [50]
2 years ago
9

Which chemical equation below is not balanced?

Chemistry
1 answer:
Effectus [21]2 years ago
6 0

Answer:

B

Explanation:

The second one is not balanced correctly.

2 NaOH + 2HNO3 → 2NaNO3 + 2 H20

I didn't notice this before but it can be balanced without the twos.

 NaOH + HNO3 → NaNO3 +  H20

It was still wrong. It needed to have the twos removed, not 2 more added. Adding two more isn't wrong, but it should be balanced without 2s if at all possible.

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nignag [31]

Eh I can't comment

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4 0
2 years ago
At 1.00 atmosphere pressure, a certain mass of a gas has a temperature of 100oC. What will be the temperature at 1.13 atmosphere
Inessa [10]

Answer:  Final temperature of the gas will be 330 K.

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T     (At constant volume and number of moles)

{P_1\times T_1}={P_2\times T_2}

where,

P_1 = initial pressure of gas   = 1.00 atm

P_2 = final pressure of gas  = 1.13 atm

T_1 = initial temperature of gas  = 100^0C=(100+273)K=373K K

T_2 = final temperature of gas  = ?

{1.00\times 373}={1.13\times T_2}

T_2=330K

Therefore, the final temperature of the gas will be 330 K.

7 0
3 years ago
Analysis of an athletes urine found the presence of a compound with a molar mass of 312 g/mol. How many moles of this compound a
rewona [7]
<h3>Answer:</h3>

= 5.79 × 10^19 molecules

<h3>Explanation:</h3>

The molar mass of the compound is 312 g/mol

Mass of the compound is 30.0 mg equivalent to 0.030 g (1 g = 1000 mg)

We are required to calculate the number of molecules present

We will use the following steps;

<h3>Step 1: Calculate the number of moles of the compound </h3>

Moles=\frac{mass}{molar mass}

Therefore;

Moles of the compound will be;

=\frac{0.030}{312g/mol}

      = 9.615 × 10⁻5 mole

<h3>Step 2: Calculate the number of molecules present </h3>

Using the Avogadro's constant, 6.022 × 10^23

1 mole of a compound contains 6.022 × 10^23  molecules

Therefore;

9.615 × 10⁻5 moles of the compound will have ;

= 9.615 × 10⁻5 moles × 6.022 × 10^23  molecules

= 5.79 × 10^19 molecules

Therefore the compound contains 5.79 × 10^19 molecules

5 0
3 years ago
2.3.12mL =<br> L*<br> O<br> a. .312<br> O b.31.2<br> O<br> C..00312<br> O d..0312
Anna11 [10]

Answer:

a..312 I guesss kkkkkkkkkkkkkkkkkk

6 0
3 years ago
9. In a period, do the number of shielding electrons change? Why do you think
Setler79 [48]

Answer:

The nuclear charge increases, but the number of inner shielding electrons stays the same.  

Explanation:

Their shielding does not change, so the effective nuclear charge — the charge felt by a valence electron — increases.

The valence electrons are pulled closer to the nucleus, decreasing the atomic radius.

For example, consider the elements of Period 3.

\begin{array}{ccccc}& & \textbf{Number of} & \textbf{Inner} & \textbf{Valence}\\\textbf{At. No.} & \textbf{Symbol} & \textbf{Protons} & \textbf{Electrons} & \textbf{Electrons}\\11& \text{Na} & 11 & 10 & 1\\12& \text{Mg} &12 & 10 & 2\\13& \text{Al} & 13 & 10 & 3 \\14& \text{Si} & 14 & 10 & 4 \\15& \text{P} & 15 & 10 & 5\\16& \text{S} & 16 & 10 & 6\\17& \text{Cl} & 17 & 10 & 7\\18& \text{Ar} & 18 & 10 & 8 \\\end{array}

The number of protons increases as you go from one element to the next, but the number of inner electrons is constant.

3 0
3 years ago
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