Answer: The overall equation will be 
Explanation:
The representation is given by writing the anode on left hand side followed by its ion with its molar concentration. It is followed by a salt bridge. Then the cathodic ion with its molar concentration is written and then the cathode.
Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.
Anode : 
Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.
Cathode : 
The number of electrons lost must be equal to the number of electrons gained , thus overall equation will be :
The first step is to focus on the parent carbon chain:nonane. This indicates a carbon chain with 9 carbon atoms. From here, on the 4th carbon from one side, place a Br functional group; on the 2nd carbon, place a I functional group; on the 5th and 6th carbon, place a CH₃ (methyl) functional group to each. Lastly, complete the bonding with H atoms. The structure is shown in the attached picture.
1.5 × 10^-6 i would think
Answer:
C
Explanation:
Chemical change is baking a cake;)
Answer:
5.00 × 10⁻⁴ mol HCl; 100 mL NaOH
Step-by-step explanation:
3. Moles of HCl
<em>Data:
</em>
V(HCl) = 500 mL
pH = 3
<em>Calculations:
</em>
pH = 3
[H₃O⁺] = 10⁻³ mol·L⁻¹
V = 500 mL × (1 L/1000 mL) = 0.500 L
Moles HCl = volume × concentration
= 0.500 L × (10⁻³ mol/1 L)
= 5.00 × 10⁻⁴ mol
4. Volume of NaOH
NaOH + HCl ⟶ NaCl + H₂O
<em>Data:
</em>
[NaOH] = 0.01 mol·L⁻¹
[HCl] = 0.02 mol·L⁻¹
V(HCl) = 50 mL
<em>Calculations:
</em>
Moles HCl = 0.050 L × (0.02 mol/1 L)
= 1.0 × 10⁻³ mol
Moles NaOH = 1.0 × 10⁻³ mol HCl × (1 mol NaOH/1 mol HCl)
= 1.0 × 10⁻³ mol NaOH
V(NaOH) = 1.0 × 10⁻³ mol NaOH × (1 L NaOH/0.01 mol NaOH)
= 0.1 L NaOH Convert to millilitres
= 100 mL NaOH
