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Viktor [21]
3 years ago
11

A 6.00 kg piece of solid copper metal at an initial temperature T is placed with 2.00 kg of ice that is initially at -10.0 ∘C. T

he ice is in an insulated container of negligible mass and no heat is exchanged with the surroundings. After thermal equilibrium is reached, there is 0.50 kg of ice and 1.50 kg of liquid water.
Required:
What was the initial temperature of the piece of copper?
Physics
1 answer:
julsineya [31]3 years ago
3 0

Answer:

T = 235.134^{\textdegree}C

Explanation:

The process is modelled after the First Law of Thermodynamics:

(6000\,g) \cdot \left(0.385\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot (T -0^{\textdegree}C ) = (2000\,g)\cdot \left(2.108\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot [0^{\textdegree}C -(-10^{\textdegree}C)] + (1500\,g)\cdot \left(334\,\frac{J}{g} \right)

The initial temperature of the piece of solid copper is:

T = 235.134^{\textdegree}C

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According to quantum physics, measuring velocity of a tiny particle with an electromagnet
lidiya [134]

Answer:

Option A.

Explanation:

In quantum physics <u>there is a law to relate the position and the momentum of the particle</u>, it says that if we know with precision where is a quantum particle, we can not know the momentum of this particle, in other words, the velocity of the particle. So, when we measure the velocity of the particle we find the correct value of the particle, but we can not determine with accuracy where is the particle. This law is known as the Heisenberg's uncertainty principle and, its expressed as follows:    

\Delta x \Delta p \geq \frac{h}{4 \pi}

<em>where Δx: is the position's uncertainty, Δp: is the momentum's uncertainty and h: is the Planck constant.</em>  

Therefore, the correct answer is A: measuring the velocity of a tiny particle with an electromagnet has no effect on the velocity of the particle. It only affects the determination of the particle's position.      

I hope it helps you!

4 0
2 years ago
I need help on this question!! Please answer asap!
valentina_108 [34]

Answer:

hub    moon     merc   saturn   sun    galaxy    deep field

Explanation:

5 0
2 years ago
An electromagnetic wave is traveling straight down toward the center of the Earth. At a certain moment in time the electric fiel
Anika [276]

Answer:

North

Explanation:

In an electromagnetic wave, the direction of the wave, the direction of the electric field and the direction of the magnetic field are all perpendicular to each other.

Therefore, we can  find the direction of the magnetic field by using the right hand rule. We have:

- Index finger: direction of motion of the wave --> toward the center of Earth

- middle finger: direction of the electric field --> west

- thumb: direction of the magnetic field --> north

So, the magnetic field points north.

3 0
3 years ago
.Ryan boiled a liter of water and then stirred sugar into it, adding more sugar until no more would dissolve in the water, creat
kaheart [24]

Answer: The correct option is that all of the sugar will come out of solution, and pure water will float to the top

Explanation:

Solution in the field of Chemistry is usually made up of two or more substances which contains a solute that dissolves in a solvent.

A solution can either be:

-> Saturated

--> Unsaturated or

-> Supersaturated.

A saturated solution is a solution with solutes that dissolves until it is unable to dissolve anymore leaving the undissolved solute beneath.

When there is mixture of a solute and a solvent in a solution the reactions that occurs are called crystallization and dissolution. Crystallization causes solid solutes to remain undissolved while dissolution is simply the dissolving process of the solute.

When Ryan added more sugar after reaching the saturation point of the mixture, the process of crystallization set in which surpassed the process of dissolution of the sugar solute leading to precipitation of the solute of out the solution.

6 0
3 years ago
a 300kg motorboat is turned off as it approaches a dock and coasts towards it at .5 m/s. Isaac, whose mass is 62 kg jumps off th
Zolol [24]

-- Before he jumps, the mass of (Isaac + boat) = (300 + 62) = 362 kg,
their speed toward the dock is 0.5 m/s, and their linear momentum is

  Momentum = (mass) x (speed) = (362kg x 0.5m/s) = <u>181 kg-m/s</u>

<u>relative to the dock</u>. So this is the frame in which we'll need to conserve
momentum after his dramatic leap.

After the jump:

-- Just as Isaac is coiling his muscles and psyching himself up for the jump,
he's still moving at 0.5 m/s toward the dock.  A split second later, he has left
the boat, and is flying through the air at a speed of 3 m/s relative to the boat.
That's 3.5 m/s relative to the dock.

    His momentum relative to the dock is (62 x 3.5) = 217 kg-m/s toward it.

But there was only 181 kg-m/s total momentum before the jump, and Isaac
took away 217 of it in the direction of the dock.  The boat must now provide
(217 - 181) = 36 kg-m/s of momentum in the opposite direction, in order to
keep the total momentum constant.

Without Isaac, the boat's mass is 300 kg, so 

                     (300 x speed) = 36 kg-m/s .

Divide each side by 300:  speed = 36/300 = <em>0.12 m/s ,</em> <u>away</u> from the dock.
=======================================

Another way to do it . . . maybe easier . . . in the frame of the boat.

In the frame of the boat, before the jump, Isaac is not moving, so
nobody and nothing has any momentum.  The total momentum of
the boat-centered frame is zero, which needs to be conserved.

Isaac jumps out at 3 m/s, giving himself (62 x 3) = 186 kg-m/s of
momentum in the direction <u>toward</u> the dock.

Since 186 kg-m/s in that direction suddenly appeared out of nowhere,
there must be 186 kg-m/s in the other direction too, in order to keep
the total momentum zero.

In the frame of measurements from the boat, the boat itself must start
moving in the direction opposite Isaac's jump, at just the right speed 
so that its momentum in that direction is 186 kg-m/s.
The mass of the boat is 300 kg so
                                                         (300 x speed) = 186

Divide each side by 300:  speed = 186/300 = <em>0.62 m/s</em>    <u>away</u> from the jump.

Is this the same answer as I got when I was in the frame of the dock ?
I'm glad you asked. It sure doesn't look like it.

The boat is moving 0.62 m/s away from the jump-off point, and away from
the dock.
To somebody standing on the dock, the whole boat, with its intrepid passenger
and its frame of reference, were initially moving toward the dock at 0.5 m/s.
Start moving backwards away from <u>that</u> at 0.62 m/s, and the person standing
on the dock sees you start to move away <u>from him</u> at 0.12 m/s, and <em><u>that's</u></em> the
same answer that I got earlier, in the frame of reference tied to the dock.

  yay !

By the way ... thanks for the 6 points.  The warm cloudy water
and crusty green bread are delicious.


4 0
3 years ago
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