Answer:
The resultant vector 
is given by ![\vec R = 3.196\,\hat{i}-0.464\,\hat{j}\,\,\,[m]](https://tex.z-dn.net/?f=%5Cvec%20R%20%3D%203.196%5C%2C%5Chat%7Bi%7D-0.464%5C%2C%5Chat%7Bj%7D%5C%2C%5C%2C%5C%2C%5Bm%5D)
.
Explanation:
Let 
and 
, both measured in meters. The resultant vector 
is calculated by sum of components. That is:
(Eq. 1)
The resultant vector is given by .
Answer:
800cm3
Explanation:
This is a general gas law question
Which has the relationship P1V1/T1 = P2V2/T2
P1= P1 in kPa
T1 = T1 in K
V1= 800cm3
V2=?
P2= 2* P1
T2= 2*T1
The volume of gas after the changes (V2), making it as the subject of formula
V2= P1*V1*T2/P2*T1
V2 = P1 *800* 2T1 / 2P1 * T1 ; dividing accordingly, we have
V2 = 800cm3
The answer using the graphical method and analytical method of vector addition will always be
C. Same
Analytic method means adding vectors (x₁,y₁) and (x₂,y₂) give (x₁+x₂,y₁+y₂)
Example: Addition of (2,3) and (1,1) gives (3,4)
Solving it graphically will also give (3,4)
Answer:
Friction force always acts tangent to the surface at points of contact. Friction force acts opposite to the direction of motion. There are 2 types of friction: Static friction: If the two surfaces in contact do not move relative to each other, one has static friction.
Answer:
21.21 m/s
Explanation:
Let KE₁ represent the initial kinetic energy.
Let v₁ represent the initial velocity.
Let KE₂ represent the final kinetic energy.
Let v₂ represent the final velocity.
Next, the data obtained from the question:
Initial velocity (v₁) = 15 m/s
Initial kinetic Energy (KE₁) = E
Final final energy (KE₂) = double the initial kinetic energy = 2E
Final velocity (v₂) =?
Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:
KE = ½mv²
NOTE: Mass (m) = constant (since we are considering the same car)
KE₁/v₁² = KE₂/v₂²
E /15² = 2E/v₂²
E/225 = 2E/v₂²
Cross multiply
E × v₂² = 225 × 2E
E × v₂² = 450E
Divide both side by E
v₂² = 450E /E
v₂² = 450
Take the square root of both side.
v₂ = √450
v₂ = 21.21 m/s
Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.
