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zloy xaker [14]
3 years ago
7

A stone is thrown, run a velocity of 15m/s is projected of an elevation of 30° to the horizontal calculate the time rate of flig

ht
Physics
1 answer:
frozen [14]3 years ago
3 0

Answer:

1.53 seconds

Explanation:

Applying,

T = 2usin∅/g................ Equation 1

Where, T = time of flight, u = initial velocity, ∅ = angle of projectile to the horizontal, g = acceleration due to gravity

From the question,

Given: u = 15 m/s, ∅ = 30°

Constant: g = 9.8 m/s²

Substitute these values in equation 1

T = 2(15)(sin30°)/9.8

T = 15/9.8

T = 1.53 seconds

Hence the time rate of flight is 1.53 seconds

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Answer:

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Explanation:

The balance condition, to keep the gate from moving, requires that the net torque be zero, this is, the torques on both sides of the gate must be equal.

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3 years ago
A projectile thrown from the ground reached a horizontal displacement of 50 [m] and a maximum height of 100 [m]. What are the ma
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Answer:

\theta=82.87^0

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Explanation:

given,

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initial velocity (v₀) = ?

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using formula

R = \dfrac{u^2sin2\theta}{g}........(1)

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dividing equation (2)/(1)

\dfrac{h}{R} = \dfrac{\dfrac{u^2sin\theta}{2g}}{\dfrac{u^2sin2\theta}{g}}

\dfrac{h}{R} =\dfrac{sin^2\theta}{2sin2\theta}

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