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REY [17]
3 years ago
12

The internal combustion engine takes advantage of the ability of the combustion reaction of gasoline to do _______ and move a pi

ston up and down.
A. free energy
B. enthalpy
C. work
D. entropy
PLS HELP ASAP THANK YOU!!!
Chemistry
1 answer:
grandymaker [24]3 years ago
8 0
The answer is C, work. The reaction of the air/gas mixture being ignited produces energy which moves the piston up and down which turns the crankshaft.
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In an aqueous chloride solution cobalt(II) exists in equilibrium with the complex ion CoCl42-. Co2 (aq) is pink and CoCl42-(aq)
kolezko [41]

Answer:

1. This reaction is <u>(A) Exothermic .</u>

2. When the temperature is decreased the equilibrium constant, K: <u>(A) Increases</u>

3.When the temperature is decreased the equilibrium concentration of Co2:<u> (A) Increases</u>

Explanation:

CoCl4^2-(aq)  Co_2+(aq) + 4Cl^-(aq)

1. The pink color predominates at low temperatures, indicating that the commodity is preferred.

This is a reaction that is <u>exothermic.</u>

2. As the decrease in the temperature , the equilibrium constant , K ;

      equilibrium constant = \frac{product}{reactant} =\frac{[CO^2^+][Cl^-^4]}{CoCl^2^-_4}

As the temperature drops, the concentration ofCl^- and CO^2^+ rises, and K rises as well , thus it <u>increases </u>.

3. The equilibrium concentration of CO^2^+ decreases as the temperature decreases:

When the temperature is lowered, the equilibrium shifts to the right , that is it <u>increases.</u>

4 0
3 years ago
If 5.0 grams of sucrose, C12H22O11, are dissolved in 10.0 grams of water, what will be the boiling point of the resulting soluti
GaryK [48]

Answer : The boiling point of the resulting solution is, 100.6^oC

Explanation :

Formula used for Elevation in boiling point :

\Delta T_b=i\times k_b\times m

or,

T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_b = boiling point of solution = ?

T^o_b = boiling point of water = 100^oC

k_b = boiling point constant  = 0.52^oC/m

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

w_2 = mass of solute (sucrose) = 5.0 g

w_1 = mass of solvent (water) = 10.0 g

M_2 = molar mass of solute (sucrose) = 342.3 g/mol

Now put all the given values in the above formula, we get:

(T_b-100)^oC=1\times (0.52^oC/m)\times \frac{(5.0g)\times 1000}{342.3\times (10.0g)}

T_b=100.6^oC

Therefore, the boiling point of the resulting solution is, 100.6^oC

5 0
3 years ago
Write a RACE paragraph to make and defend a claim about how salinity and temperature impact ocean density .
djverab [1.8K]

Answer:

Explanation:

Girl. No one is about to write a paragraph for you. Research, collect information and attempt it on your own. We are here to help, not to do your work for you.

7 0
3 years ago
Calculate the molality of acetone in an aqueous solution with a mole fraction for acetone of 0.241. Answer in units of m.
Anit [1.1K]

Answer: The molality of solution is 17.6 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molarity=\frac{n}{W_s}

where,

n = moles of solute

W_s = weight of solvent in kg

moles of acetone (solute) = 0.241

moles of water (solvent )= (1-0.241) = 0.759

mass of water (solvent )= moles\times {\text {Molar Mass}}=0.759\times 18=13.7g=0.0137kg

Now put all the given values in the formula of molality, we get

Molality=\frac{0.241}{0.0137kg}=17.6mole/kg

Therefore, the molality of solution is 17.6 mole/kg

3 0
3 years ago
20 POINTS HURRY!!!
uysha [10]

Answer:

C. commensalism.

Explanation:

Here is the answer

4 0
3 years ago
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