Question

A force of 2.0 n exerted on an object for 0.1 seconds increases the objects velocity by 1.0 m/s you what is the mass of the object?

Answer 1

Answer:

The mass of the object is 0.2 kg

Explanation:

The magnitude of the applied force = 2.0 N

The duration of application of the force = 0.1 second

The increase in velocity given to the body by the force = 1.0 m/s

From the equation of motion under acceleration, we have;

v = u + a·t

Therefore;

a = (v - u)/t

Where;

v = The final velocity

u = The initial velocity

t = The time taken for the change in velocity = 0.1 s

Given that the change in velocity = 1 m/s, we have;

v - u = 1 m/s

∴ a = (v - u)/t = 1 m/s/(0.1 s) = 10 m/s²

The acceleration, a = 10 m/s²

The equation for the applied force, F is F = Mass, m × Acceleration, a

Therefore, when the applied force, F = 2.0 N, and the acceleration, a is a = 10 m/s², we have;

F = Mass, m × Acceleration, a

2.0 N = Mass of the object × 10 m/s²

∴ Mass of the object = 2.0 N/10 m/s² = 0.2 kg

The mass of the object = 0.2 kg.