Question

Calculate the volume of sulfur dioxide produced when 27.9 mL O2 reacts with carbon disulfide.

Answer 1

Answer:

18.6 ml

Explanation:

From the balanced equation given:

Volume of oxygen = 27.9 mL

From the equation, we will see that three moles of oxygen react with CS_2 to give two moles of sulfur dioxide (SO_2)

Also, three mL of O_2 yields two mL of SO_2

Now, to calculate the volume of SO_2; we have:

$=27.9 mL \times \dfrac{2 mL \ of SO_2}{3 mL \ O_2}$

= 18.6 mL of SO_2