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3 years ago

15

If we add the number in that constant term is there will also be independence between them?(case of refractI've index of medium)

1 answer:

serious [3.7K]3 years ago

8 0

Answer:

Yes

Explanation:

n1 sinθ1 = n2 sinθ2, where θ1 and θ2 are the angles of incidence and refraction.

$n=\frac{c}{v}$

changing D between them will not affect dependence

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4. Johnny exerts a 3.55 N rightward force on a 0.200-kg box to accelerate it across a low-friction track. If the total resistanc

muminat

a) $15.2 m/s^2$

b) 1.96 N

c) 1.96 N

Explanation:

a)

To find the acceleration of the box, we apply Newton's second law of motion:

$\sum F=ma$

where

$\sum F$ is the net force on the box

m is the mass of the box

a is its acceleration

Here we have to consider the horizontal direction, which is the one in which the box is moving. The net force is given by:

$\sum F=3.55 N - 0.52 N=3.03 N$

which is the difference between the forward force and the resistive force. Then we have

m = 0.200 kg (mass of the box)

Therefore, the acceleration of the box is:

$a=\frac{\sum F}{m}=\frac{3.03}{0.200}=15.2 m/s^2$

b)

The gravitational force (also called weight) is the force with which an object is pulled by the Earth towards the Earth's centre.

It is given by

$F_g = mg$

where

m is the mass of the object

g is the acceleration due to gravity

In this problem, we have:

m = 0.200 kg is the mass of the box

$g=9.8 m/s^2$ is the acceleration due to gravity

Therefore, the gravitational force on the box is:

$F_g=(0.200)(9.8)=1.96 N$

c)

The normal force is the force with which a surface pushes back on an object.

For an object lying on a flat surface, there are two forces acting along the vertical direction:

- The gravitational force, $F_g$ , which pushes the object downward

- The normal force, N, which pushes the object upward

As the object is at rest, the vertical acceleration of the object is zero, therefore according to Newton's second law of motion, the net force must be zero:

$\sum F=F_g-N=0$

Which means that the normal force is equal to the gravitational force:

$N=F_g$

And so, for the box in this problem, the normal force is

$N=1.96 N$

6 0

4 years ago

How long does it take Larry to run 200 meters running at a speed of 21 m/s

andreev551 [17]

Answer:

9.52 seconds

Explanation:

t = d/v

t = 200 / 21

t = 9.52s (to 3 s.f.)

6 0

2 years ago

Read 2 more answers

a boy is riding a bicycle at a velocity of 5.0 m/s. he applies the brakes and uniformly decelerates to a stop at a rate of 2.5 m

JulijaS [17]

The working equation would be Vf (final velocity) = Vi (initial velocity) + a (acceleration) t (time). The given data are the initial velocity (5.0 m/s), acceleration (-2.5 m/s^2, negative since it is said to decelerate) and the final velocity (0 m/s, since it will put to a stop). The time would be 2 seconds.

3 0

4 years ago

What is the value of the charge that experiences a force of 2.4 Ã— 10â€“3 n in an electric field of 6.8 Ã— 10â€“5 n/c?

tia_tia [17]

Answer:

The value of charge is 35.3 C

Explanation:

Given:

Force $F = 2.4 \times 10^{-3}$ N

Electric field $E = 6.8 \times 10^{-5} \frac{N}{C}$

According coulomb's law,

$F = qE$

Where $q =$ charge that experience a force,

For finding the value of charge,

$q = \frac{F}{E}$

$q = \frac{2.4 \times 10^{-3} }{6.8 \times 10^{-5} }$

$q = 35.3$ C

Therefore, the value of charge is 35.3 C

6 0

3 years ago

Is a battery a resistor

-Dominant- [34]

A battery is a real-life voltage source. A battery can be thought of as a perfect voltage source with a small resistor (called internal resistance) in series. ... The terminal voltage equals the emf minus the voltage drop across the internal resistance (current of the external circuit times the internal resistance.)

4 0

3 years ago