Given, half life of a certain radioactive element = 800 years.
Amount of substance remaining at time t = 12.5%
Lets consider the initial amount of the radioactive substance = 100%
Using the half life equation:
A = A₀(1/2)^t/t₁/₂
where A₀ is the amount of radioactive substance at time zero and A is the amount of radioactive substance at time t, and t₁/₂ is the half-life of the radioactive substance.
Plugging the given data into the half life equation we have,
12.5 = 100 . (1/2)^t/800
12.5/100 = (1/2)^t/800
0.125 = (0.5)^t/800
(0.5)^3 = (0.5)^t/800
3 = t/800
t = 2400 years
Thus the object is 2400 years old.
Answer: 1. Complete Nuclear Symbol : 
2. Atomic number : 22
3. Mass number : 48
4. Charge : 4 +
Explanation:
Atomic number is equal to the number of protons.
Mass number is the sum of number of neelectrons. utrons and number of protons.
Given : no of protons = 22 , thus atomic number = 22
Mass number = number of neutrons + number of protons
Mass number = 26 + 22 = 48
Also for a neutral atom , the number of protons is equal to the number of electrons. But here electrons are 4 less than protons, which means the atom has lost 4 electrons and thus will have a charge of 4+.
The atomic number is specific to an element, and the element with atomic number 22 is Titanium (Ti). The representation is 
73.606 °C is the freezing point of the solution made with with 1.31 mol of CHCl3 in 530.0 g of CCl4.
Explanation:
Data given:
number of moles of CHCl3 = 1.31 moles
mass of solvent CHCl3 = 530 grams or 0.53 kg
Kf = 29.8 degrees C/m
freezing point of pure solvent or CCl4 = -22.9 degrees
freezing point = ?
The formula used to calculate the freezing point of the mixture is
ΔT = iKf.m
m= molality
molality = 
putting the value in the equation:
molality= 
= 2.47 M
Putting the values in freezing point equation
ΔT = 1.31 x 29.8 x 2.47
ΔT = 73.606 degrees
<span>Get into moles first. .0590 grams over 540.8 grams per mole = 1.09 x l0^-4 moles
Sr3(As04)2 = 3 Sr++(aq) plus 2 As04^-3(aq)
Ksp = (Sr++)^3(As04^-3)^2
(Sr++) = 3 X l.09 x l0^-4 = 3.27 x l0^-4
(As04^-3) = 2 x l.09 x l0^-4 = 2.18 x l0^-4
<span>Ksp = (3.27 x l0^-4)^3 (2.18 x l0^-4)^2 which equals 1.66 x 10^-18th
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