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2 years ago

If you observe a Full Moon on January 12th, on what date would you observe the next New Moon?

Chemistry

1 answer:

AlexFokin [52]2 years ago

8 0

January 19

Explanation:

every first 7 days of a month the moon roughly starts its full moon phase

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Is KNO a strong acid?

stira [4]

Answer:

First of all, it's KNO₃ not KNO.

Second, KNO₃ is neither an acid nor it is a base, infact, it is a salt and therefore it's neutral.

hope that helps...

3 0

2 years ago

How many grams are in 9.05 x 1023 atoms of silicon?

Sergeu [11.5K]

Explanation:

Number of moles(n)=Number of atoms(N)/Avogadro's constant.

Avogadro's constant=6.02×10²³

so we have

n=9.05×10²³/6.02×10²³

n=1.0503moles.

n=mass/molar mass

1.0503=mass/28

mass=1.0503×28

mass=29.4084g

6 0

2 years ago

How many liters are in .0025 millililiters

jekas [21]

Answer: 0.0000025 liters

8 0

2 years ago

ALUMINUM (AI) + NITRATE (NO3)

anzhelika [568]

Answer:

Al(No3)3

Explanation:

hope this is correct....

7 0

2 years ago

The Kp for the reaction below is 1.49 × 108 at 100.0°C:CO(g) + Cl2(g) → COCl2(g)In an equilibrium mixture of the three gases, PC

Serggg [28]

Answer: The equilibrium partial pressure of phosgene is 7.34 atm

Explanation:

The given chemical equation follows:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

The expression of $K_p$ for above equation follows:

$K_p=\frac{p_{COCl_2}}{(p_{CO})\times (p_{Cl_2})}$

We are given:

Equilibrium partial pressure of CO = $2.22\times 10^{-4}atm$

Equilibrium partial pressure of chlorine gas = $2.22\times 10^{-4}atm$

$K_p=1.49\times 10^8$

Putting values in above equation, we get:

$1.49\times 10^8=\frac{p_{COCl_2}}{(2.22\times 10^{-4})\times (2.22\times 10^{-4})}\\\\p_{COCl_2}=7.34atm$

Hence, the equilibrium partial pressure of phosgene is 7.34 atm

7 0

3 years ago